Question

The initial velocity of a car moving along a straight path was 0 meters/second. After 10 seconds, it reached a velocity of 25 meters/second. Calculate the car’s average acceleration during this time period.

Answer 1

Answer:

$2.5m/s^{2}$

Explanation:

We can use one of the kinematics equation to find the acceleration.

v = u + at

where v = final velocity, in m/s

u = initial velocity, in m/s

t = time in seconds

Given the information provided from the question,

v = 25m/s

u = 0m/s

t = 10s

Substitute these values into the kinematics equation.

25 = 0 + 10a

10a = 25

a = 25 / 10

= $2.5m/s^{2}$