Answer:
a. Sally did not take account the atoms of the compounds, because she only summed Al + O and in the oxide, we have 2 mol of Al and 3 mol of O
b. The conversion factor that Jacob did, was wrong.
Moles must be divided by moles, so they can be cancelled. The correct conversion factor is:
9.45 mol . 102 g / 1 mol = 963.9 g
Explanation:
Al₂O₃ → Aluminum oxide
We determine the molar mass:
Molar mass Al . 2 + Molar mass O . 3
27 g/mol . 2 + 16 g/mol . 3 = 102 g/mol
a. Sally did not take account the atoms of the compounds, because she only summed Al + O and in the oxide, we have 2 mol of Al and 3 mol of O
b. The conversion factor that Jacob did, was wrong.
Moles must be divided by moles, so they can be cancelled. The correct conversion factor is:
9.45 mol . 102 g / 1 mol = 963.9 g
The question is incomplete, here is the complete question:
428. mg of an unknown protein are dissolved in enough solvent to make 5.00 mL of solution. The osmotic pressure of this solution is measured to be 0.0766 atm at 25.0°C. Calculate the molar mass of the protein. Round your answer to 3 significant digits
<u>Answer:</u> The molar mass of protein is 
<u>Explanation:</u>
To calculate the concentration of solute, we use the equation for osmotic pressure, which is:

Or,

where,
= osmotic pressure of the solution = 0.0766 atm
i = Van't hoff factor = 1 (for non-electrolytes)
Mass of solute (protein) = 428 mg = 0.428 g (Conversion factor: 1 g = 1000 mg)
Volume of solution = 5.00 mL
R = Gas constant = 
T = temperature of the solution = ![25^oC=[273+25]=298K](https://tex.z-dn.net/?f=25%5EoC%3D%5B273%2B25%5D%3D298K)
Putting values in above equation, we get:

Hence, the molar mass of protein is 
Answer:
holding a basketball in the air
Explanation:
the ball has potential to have a certain amount of energy but hasn't exerted it yet.