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Maru [420]
2 years ago
11

If a radioactive decay produced 1.26 × 1012 J of energy, how much mass was lost in the reaction?

Chemistry
1 answer:
Ket [755]2 years ago
8 0

The mass lost in the process is 1.4 * 10^-5Kg.

<h3>What is the Einstein equation?</h3>

The Einstein equation is able to relate the mass lost to the energy that is evolved in a nuclear process.

Given that;

E = Δmc^2

Δm = E/c^2

Δm =  1.26 × 10^12 J/( 3 * 10^8)^2

Δm = 1.4 * 10^-5Kg

Learn more about Einstein equation:brainly.com/question/10809666

#SPJ1

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Calculate the fraction of atoms in a sample of argon gas at 400 K that have an energy of 12.5 kJ or greater. Report your answer
emmainna [20.7K]

Answer:

0.023

Explanation:

The Arrhenius' equation states that:

k = A*e^{\frac{-Ea}{RT}

Where k is the velocity constant of the reaction, A is the constant of the collisions, Ea is the activation energy (the energy necessary to the molecules have so the reaction will happen), R is the gas constant (8.314 J/molK) and T is the temperature.

This equation is derivated of:

k = pZf

Where

p=fraction of collisions that occur with reactant molecules properly oriented

f=fraction of collisions having energy greater than the activation energy

Z=frequency of collisions

Thus, p*Z = A, and

f = e^{\frac{-Ea}{RT} }

So, if the energy of the molecules is 12.5 kJ/mol = 12500 J/mol, thus the fraction will be:

f = e^{\frac{-12500}{8.314*400} }

f = 0.023

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Write the manufacturing process of oxygen gas from liquid air​
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Answer:

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