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2 years ago

What do electricians call disconnects or disconnecting?

Physics

1 answer:

muminat2 years ago

4 0

Service disconnect
this is the first disconnect device after the utility meter.

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A 540 g model rocket is on a cart that is rolling to the right at a speed of 2.5 m/s. The rocket engine, when it is fired, exert

frez [133]

Answer:

horizontal distance left of the loop should you launch is 7.1m

Explanation:

See attached file

4 0

3 years ago

How can an athlete participating in a 40m sprint modify and improve their performance based on the kinematic variable of speed a

aleksandrvk [35]

The athlete can improve performance by building strength, coordination and balance.

<h3>Who is an Athlete?</h3>

This is an individual who is proficient in sports and other forms of physical exercise.

Improvement of performance based on the kinematic variable of speed and acceleration can be achieved by building strength, coordination and balance by performing plyometric exercises etc.

Read more about Athlete here brainly.com/question/1532968

5 0

3 years ago

A magnetic field is aligned perpendicular to the plane of a circular loop of wire with radius 5.0 cm and 20 turns. The magnetic

Mariana [72]

Answer:

$V = 0.157(-36 e^{-3t} + 1.5)$

$t = 1.24 s$

Part b)

$EMF = 0.136(-36e^{-3t} + 1.5)$

Explanation:

magnetic field due to external source is given as

$B = 12 e^{-3t} + 1.5 t + 6$

area of the loop is given as

$A = \pi r^2$

$A = \pi(0.05)^2$

$A = 7.85 \times 10^{-3} m^2$

Now we have

$\phi = NBAcos0$

$\phi = (20)(12e^{-3t} + 1.5t + 6)(7.85 \times 10^{-3})$

$V = \frac{d\phi}{dt}$

$V = 0.157\frac{d}{dt}(12e^{-3t} + 1.5t + 6)$

$V = 0.157(-36 e^{-3t} + 1.5)$

now we need to find the time at which voltage is 0.1 Volts so we have

$0.1 V = 0.157(-36e^{-3t} + 1.5)$

$t = 1.24 s$

Part b)

If magnetic field is inclined at an angle of 30 degree with the normal of the loop then

$\phi = NBAcos30$

now we know that induced EMF is given as

$EMF = \frac{d\phi}{dt}$

$EMF = NAcos30\frac{dB}{dt}$

$EMF = (20)(7.85 \times 10^{-3})cos30(\frac{d}{dt}(12e^{-3t} + 1.5t + 6))$

$EMF = 0.136(-36e^{-3t} + 1.5)$

7 0

3 years ago

Help please! Test tomorrow!

dlinn [17]

Earth distance to the Sun is about 40 times the Moon's distance from earth.

<u>Explanation:</u>

The Earth's distance from the Sun is about 93 million miles. When it expressed in Km, it is 150 million Km.
The Moon's distance from Earth is 238,855 miles. When it is 40 times then it will approximately equal to 93 million miles.
The Sun's distance from Venus is 67.237 million miles. The Sun's distance from mercury is 35.832 million miles.

7 0

4 years ago

PLEASE HELP!! DUE SOON!!!

Alecsey [184]

The answer is D, all responses are correct

7 0

3 years ago

Read 2 more answers