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3 years ago

Somebody help me with this please very much appreciated

Chemistry

1 answer:

Flauer [41]3 years ago

7 0

The answer for the following answer is explained below.

The answer is NH_{4} ^{+}

Explanation:

Bronsted-Lowry acid :

It is a solution that donates protons, and is known as a proton donor.It donates protons in the form of hydrogen ion( $H^{+}$ ).This is reinforced by the definition of an acid ,which is a solution that has hydrogen ions.

In Bronsted-Lowry aci it must contain a hydrogen io that it can give up.When the acid gives a hydrogen ion,the charge of an acid decreases.

Here,

NH_{4} ^{+} loses one hydrogen ion and forms ammonia molecule.

So therefore the Bronsted-Lowry acid is NH_{4} ^{+}.

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What statement best describes the compresibility of a gas?

Misha Larkins [42]

Answer: A gas molecules have high kinetic energy due to which they have move rapidly from one place to another

Explanation:

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3 years ago

if 45.0 ml of 1.50 M Ca(OH)2 are needed to neutralize 25.0 ml of HI of unknown concentration, what is the molarity of the HI?

ipn [44]

Answer:

M of HI = 5.4 M.

Explanation:

We have the rule: at neutralization, the no. of millimoles of acid is equal to the no. of millimoles of the base.

(XMV) acid = (XMV) base.

where, X is the no. of (H) or (OH) reproducible in acid or base, respectively.

M is the molarity of the acid or base.

V is the volume of the acid or base.

(XMV) HI = (XMV) Ca(OH)₂.

For HI; X = 1, M = ??? M, V = 25.0 mL.

For Ca(OH)₂, X = 2, M = 1.5 M, V = 45.0 mL.

∴ M of HI = (XMV) Ca(OH)₂ / (XV) HI = (2)(1.5 M)(45.0 mL) / (1)(25.0 mL) = 5.4 M.

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4 years ago

Why are you people eating typods??????????????????????????

Setler79 [48]

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5 0

3 years ago

Read 2 more answers

Nitrogen dioxide (NO2) cannot be obtained in a pure form in the gas phase because it exists as a mixture of NO2 and N2O4. At 16°

Pavel [41]

Answer:

PNO₂ = 0.49 atm

PN₂O₄ = 0.45 atm

Explanation:

Let's begin with the equation of ideal gas, and derivate from it an equation that involves the density (ρ = m/V).

PV = nRT

n = m/M (m is the mass, and M the molar mass)

$PV = \frac{m}{M}RT$

$PxM = \frac{m}{V}RT$

PxM = ρRT

ρ = PxM/RT

With the density of the gas mixture, we can calculate the average of molar mass (Mavg), with the constant of the gases R = 0.082 atm.L/mol.K, and T = 16 + 273 = 289 K

$2.7 = \frac{0.94xMavg}{0.082x289}$

0.94Mavg = 63.9846

Mavg = 68.0687 g/mol

The molar mass of N is 14 g/mol and of O is 16 g/mol, than $M_{NO2} = 46$ g/mol and $M_{N2O4} = 96$ g/mol. Calling y the molar fraction:

$Mavg = M_{NO2}y_{NO2} + M_{N2O4}y_{N2O4}$

And,

$y_{NO2} + y_{N2O4} = 1$

$y_{N2O4} = 1 - y_{NO2}$

So,

$68.0687 = 46y_{NO2} + 92x(1 - y_{NO2})$

$68.0687 - 92 = 46y_{NO2} - 92y_{NO2}$

$46y_{NO2} = 23.9313$

$y_{NO2} = 0.52$

$y_{N2O4} = 0.48$

The partial pressure is the molar fraction multiplied by the total pressure so:

PNO₂ = 0.52x0.94 = 0.49 atm

PN₂O₄ = 0.48x0.94 = 0.45 atm

8 0

3 years ago

Calculate the moles of SO2 that contains 3.8 moles of O atoms

Olegator [25]

Answer: 1.9 moles SO₂

Explanation:

1) The chemical formula SO₂ shows that for every mol of SO₂ there are 1 mol of S and two moles of O.

2) Then you can state the proportion between the number of moles of SO₂ and O to find how many moles of SO₂:contains 3.8 moles of O.

   1 mol SO₂                         x

-------------------- =   --------------------------

    2 moles O              3.8 moles O

3) Now, you can clear x:

x = 3.8 moles O × 1 mol SO₂ / 2 moles O.

x = 1.9 moles SO₂.

5 0

3 years ago