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mestny [16]
3 years ago
5

Somebody help me with this please very much appreciated

Chemistry
1 answer:
Flauer [41]3 years ago
7 0

The answer for the following answer is explained below.

The answer is NH_{4} ^{+}

Explanation:

Bronsted-Lowry acid :

It is a solution that donates protons, and is known as a proton donor.It donates protons in the form of hydrogen ion(H^{+}).This is reinforced by the definition of an acid ,which is a solution that has hydrogen ions.

In Bronsted-Lowry aci it must contain a hydrogen io that it can give up.When the acid gives a hydrogen ion,the charge of an acid decreases.

Here,

NH_{4} ^{+}  loses one hydrogen ion and forms ammonia molecule.

So therefore the Bronsted-Lowry acid  is NH_{4} ^{+}.

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Hope this helps!
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Answer:

I can't draw diagrams on this web site but I can do with numbers I think. So an electron is moved from n = 1 to n = 5. I'm assuming I've interpreted the problem correctly; if not you will need to make a correction. I'm assuming that you know the electron in the n = 1 state is the ground state so the 4th exited state moves it to the n = 5 level.

n = 5 4th excited state

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n = 3 2nd excited state

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To find the E for any transition (delta E) take E for upper n and subtract from the E for the lower n and that gives you delta E for the transition.

So for n = 5 to n = 1, use -Efor 5 -(-Efor 1) = + something which I'll leave for you. You could convert that to wavelength in meters with delta E = hc/wavelength. You might want to try it for the Balmer series (n ending in n = 2). I think the red line is about 650 nm.

Explanation:

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Have a nice day

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