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serious [3.7K]
3 years ago
11

A plane electromagnetic wave, with wavelength 2.8 m, travels in vacuum in the positive direction of an x axis. the electric fiel

d, of amplitude 260 v/m, oscillates parallel to the y axis. what are the (a) frequency, (b) angular frequency, and (c) angular wave number of the wave
Physics
1 answer:
Arte-miy333 [17]3 years ago
3 0
Ok first you gotta know what they are actually even asking you.

Frequency = <em>wavelengths per second
</em>Angular Frequency = <em>radians per second
</em>Wave Number = <em>wavelengths per meter
</em>Angular Wave Number = <em>radians per meter</em>
<em /><em />
Frequency is Easy, just divide the speed of light by the wavelength. This is your answer for A.

Angular frequency is how many radians per second the ELECTRIC FIELD moves through over one second. We know that there are 2π radians in one wavelength.

So to get the angular frequency just multiply the regular frequency by 2π (6.28) to get the frequency in terms of radians per second (<em>instead of waves per second</em><em />). This is your answer for B.

The wave number of a photon is how many waves <em>per meter</em> the photon moves through rather than waves <em>per second</em><em>, </em>similar but different to the 'frequency' calculations above.

Simply find the waves per meter (1 meter divided by the <em>wavelength</em>) and multiply by 2π to get the <em>radians per meter</em><em />. this is your answer for C.

NOTE: make sure your units are all correct, wavelength in meters, frequency in Hz etc...


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Answer:

The ladder is moving at the rate of 0.65 ft/s

Explanation:

A 16​-foot ladder is leaning against a building. If the bottom of the ladder is sliding along the pavement directly away from the building at 2 ​feet/second. We need to find the rate at which the top of the ladder moving down when the foot of the ladder is 5 feet from the​ wall.

The attached figure shows whole description such that,

x^2+y^2=256.........(1)

\dfrac{dx}{dt}=2\ ft/s

We need to find, \dfrac{dy}{dt} at x = 5 ft

Differentiating equation (1) wrt t as :

2x.\dfrac{dx}{dt}+2y.\dfrac{dy}{dt}=0

2x+y\dfrac{dy}{dt}=0

\dfrac{dy}{dt}=-\dfrac{2x}{y}

Since, y=\sqrt{256-x^2}

\dfrac{dy}{dt}=-\dfrac{2x}{\sqrt{256-x^2}}

At x = 5 ft,

\dfrac{dy}{dt}=-\dfrac{2\times 5}{\sqrt{256-5^2}}

\dfrac{dy}{dt}=0.65

So, the ladder is moving down at the rate of 0.65 ft/s. Hence, this is the required solution.

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3 years ago
5) What type of substance can seep<br> groundwater and make it unusable?
sergeinik [125]

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I believe <u>chemicals</u>, though I might be wrong.

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C,d,or e you can use the process of elimination to decide...
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A scientist designed a foam container to help keep frozen foods from melting. Which best explains how the foam works?
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I think the answer should be D.<span>It reduces the amount of thermal energy that is transferred from outside to inside the container. </span>
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Two large conducting parallel plates A and B are separated by 2.4 m. A uniform field of 1500 V/m, in the positive x-direction, i
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d KE= 300*3600 v = 1.08 MeV

6 0
3 years ago
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