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DIA [1.3K]
3 years ago
7

Which of these factors control ocean currents? select the two correct answers.

Physics
1 answer:
3241004551 [841]3 years ago
0 0

Answer:

water temperatures and global wind is correct dont listen to the other one i got it incorrect because of them

Explanation:

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What is the kinetic energy in joules of a 0.05. kg bullet traveling 310 m/s
Wittaler [7]
The formula is=1/2(m x v^2)

so = 1/2*(0.05)*(310)^2

ans is =2402.5 joules
3 0
3 years ago
Can I put an “I” for an argumentative essay?
masha68 [24]

Answer:

There is no place for first person in formal academic argumentative essay. However, you can use first person only if it has been asked to provide your personal opinion or reflection about the topic.

Explanation:

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3 years ago
Veolocity increases with
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Velocity increases with speed
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If an object has a mass of 20 kg, what is the force of gravity acting on it on earth? A. 32.67 N B. 2.04 kg C. 1.96 kg D. 196 N
Brilliant_brown [7]
M=20 kg
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7 0
3 years ago
Read 2 more answers
For this problem, we assume that we are on planet-i. the radius of this planet is r =4200 km, the gravitational acceleration at
Minchanka [31]
The expression commonly used for potential gravitational energy is just simplification. It is actually just the first term in Taylor expansion of the real expression. 
In general, the potential energy of gravitational field is defined as:
U=-G \frac{mM}{r}
Where G is universal gravitational constant, and r is the distance between the objects centers of mass. Negative sign represents the bound state.
Since we are not given the mass of the planet we have to calculate it.
F_g=G\frac{mM}{r_p^2}\\ mg=G\frac{mM}{r_p^2}\\ g=G\frac{M}{r_p^2}
This formula can be used for any planet. It gives you the gravitational acceleration on the planet's surface. We can use it to calculate the planet's mass:
g=G\frac{M}{r_p^2}\\ M=\frac{gr_p^2}{G}=2.41\cdot 10^{24}kg
Now we can calculate the potential energy of that cannonball when it reaches its maximum height.
U=-G \frac{mM}{r}\\ U=-G \frac{mM}{r_p+h}
When we plug in the numbers we get:
U=-4.99\cdot 10^{10} J
The potential energy has to be equal to the kinetic energy.
E_k=4.99\cdot 10^{10} J

3 0
3 years ago
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