Answer:
7.55 km/s
Explanation:
The force of gravity between the Earth and the Hubble Telescope corresponds to the centripetal force that keeps the telescope in uniform circular motion around the Earth:

where
 is the gravitational constant
 is the gravitational constant
 is the mass of the telescope
 is the mass of the telescope
 is the mass of the Earth
 is the mass of the Earth
 is the distance between the telescope and the Earth's centre (given by the sum of the Earth's radius, r, and the telescope altitude, h)
 is the distance between the telescope and the Earth's centre (given by the sum of the Earth's radius, r, and the telescope altitude, h)
v = ? is the orbital velocity of the Hubble telescope
Re-arranging the equation and substituting numbers, we find the orbital velocity:

 
        
             
        
        
        
Answer:
  a =( -0.32 i ^ - 2,697 j ^)  m/s²
Explanation:
This problem is an exercise of movement in two dimensions, the best way to solve it is to decompose the terms and work each axis independently.
 Break down the speeds in two moments
initial
   v₀ₓ = v₀ cos θ
   v₀ₓ = 5.25 cos 35.5
 v₀ₓ = 4.27 m / s
    = v₀ sin θ
 = v₀ sin θ
   = 5.25 sin35.5
= 5.25 sin35.5
  = 3.05 m / s
 = 3.05 m / s
Final
 vₓ = 6.03 cos (-56.7)
 vₓ = 3.31 m / s
  = v₀ sin θ
 = v₀ sin θ
  = 6.03 sin (-56.7)
 = 6.03 sin (-56.7)
  = -5.04 m / s
 = -5.04 m / s
Having the speeds and the time, we can use the definition of average acceleration that is the change of speed in the time order
     a = ( - v₀) /t
 - v₀) /t
     aₓ = (3.31 -4.27)/3 
     aₓ = -0.32 m/s²
      = (-5.04-3.05)/3
 = (-5.04-3.05)/3
     =  -2.697 m/s²
 =  -2.697 m/s²
 
        
             
        
        
        
Answer:
 
 
Explanation:
Resistivity is given by  where A is cross-sectional area, R is resistance, L is the length and
 where A is cross-sectional area, R is resistance, L is the length and  is the reistivity. Substituting 0.0625 for R, 3.14 × 10-6 for A and 3.5 m for L then the resistivity is equivalent to
 is the reistivity. Substituting 0.0625 for R, 3.14 × 10-6 for A and 3.5 m for L then the resistivity is equivalent to
  
 
 
        
             
        
        
        
Resultant force= (2*6^2)^(1/2)
 =8.5m/s
answer is B.