Which type of cloud is often taken to be a sign of fair weather?.

Water flows through a 0.5 cm diameter pipe connected to a 1 cm diameter pipe. Compared to the speed of the water in the 0.5 cm p

elena55 [62]

A

Answer:

Speed of water in the 0.5cm diameter will be faster because it has a smaller area

Since area x radius ² so if radius is reduced by 0.5 speed is increased by 4times in the 0.5 diameter pipe

3 0

3 years ago

I want to make a Twinkie splat when I throw it off a building. Because Twinkies are notoriously hard to crush, I want it to hit

Monica [59]

Answer:

$s=253.6524712 \approx 253.7$

Explanation:

From the question we are told that

Initial speed $v=8ft/s$

Final speed $v=128ft/s$

Generally the Newtons equation of motion is mathematically represented by

$V_f^2-V_0^2=2as$

with

Therefore

$a=g=>9.81m/s^2\\a=32.17ft/s^2$

Therefore

$128^2-8^2=2*(32.17)*s$

$16320=2*(32.17)*s$

$s=\frac{16320}{2*(32.17)}$

$s=253.6524712 \approx 253.7$

3 0

3 years ago

An astronaut carrying a camera in space finds herselfdrifting away from a space shuttle after her tetherbecomes unfastened. If s

Dahasolnce [82]

Answer:

Explanation:

According to the conservation of momentum, if she throws the camera in the opposite direction of space shuttle, she drifts towards the shuttle.

5 0

3 years ago

An athlete at high performance inhales 4.0L of air at 1 atm and 298 K. The inhaled and exhaled air contain 0.5% and 6.2% by volu

LenaWriter [7]

To solve this problem we will calculate the total volume of inhaled and exhaled water. From the ideal gas equation we will find the total number of moles of water.

An athlete at high performance inhales 4.0L of air at 1atm and 298K.

The inhaled and exhaled air contain 0.5% and 6.2% by volume of water, respectively.

During inhalation, volume of water taken is

$V_i = (4L)(0.5\%)$

$V_i = 0.02L$

During exhalation, volume of water expelled is

$V_e = (4L)(6.2\%)$

$V_e = 0.248L$

During 40 breathes, total volume of water taken is

$V_{it} = (40L)(0.02L) = 0.8L$

During 40 breathes, total volume of water expelled out is

$V_{et} = (40L)(0.248L) = 9.92L$

Therefore resultant volume of water expelled out from the lung is

$\Delta V = 9.92L-0.8L = 9.12$

From the body through the lung we have that

$n = \frac{PV}{RT}$

Here,

P = Pressure

R= Gas ideal constant

T= Temperature

V = Volume

Replacing,

$n = \frac{(1atm)(9.12L)}{(8.314J/mol \cdot K)(298K)}$

$n = 0.373mol/min$

Therefore the moles of water per minute are expelled from the body through the lungs is 0.373mol/min

8 0

4 years ago

A skier is gliding along at 4.2 m/s on horizontal, frictionless snow. He suddenly starts down a 10° incline. His speed at the bo

WARRIOR [948]

Answer:

a) 90m

b) 8.1s

Explanation:

The shortest way to finding the length of the incline is to apply an energetic analysis to determine the height of the incline. At the beginning, there is potential and kinetic energy that will turn into kinetic energy only:

$mgh+\frac{1}{2}mv_{0}^{2} =\frac{1}{2}mv_{f}^{2}$

Before we input any information, let's solve for h:

$mgh+\frac{1}{2}mv_{0}^{2} =\frac{1}{2}mv_{f}^{2}}\\\\m(gh+\frac{v_{0}^{2}}{2})=\frac{1}{2}mv_{f}^{2}}\\\\gh+\frac{v_{0}^{2}}{2}=\frac{v_{f}^{2}}{2}\\\\gh=\frac{1}{2}(v_{0}^{2}-v_{f}^{2})\\\\h=\frac{1}{2g}(v_{0}^{2}-v_{f}^{2})=\frac{1}{2*9.8\frac{m}{s^{2}}}(4.2\frac{m}{s}^{2}-18\frac{m}{s}^{2})=15.63m$

Using a sine formula we can solve for $l$ :

$Sin(10)=\frac{h}{l}\\\\l=\frac{h}{Sin(10)}=\frac{15.63m}{0.17}=90m$

In order to find the time we will use the distance formula and final velocity formula as a system of equations to solve for t:

$X=V_{0}t+\frac{at^2}{2}\\\\V_f=V_0+at$

Since the acceleration and time are both variables we will solve for acceleration in the final velocity formula and replace in the distance formula:

$V_f=V_0+at\\V_f-V_0=at\\\frac{V_f-V_0}{t}=a\\\\l=V_0t+\frac{(\frac{V_f-V_0}{t})t^2}{2}\\l=V_0t+\frac{(V_f-V_0)t}{2}\\l=t(V_0+\frac{V_f-V_0}{2})\\\\t=\frac{l}{V_0+\frac{V_f-V_0}{2}}=\frac{90m}{4.2\frac{m}{s}+\frac{18\frac{m}{s}-4.2\frac{m}{s}}{2}}=8.1s$

7 0

3 years ago