Which type of cloud is often taken to be a sign of fair weather?.

If block D weighs 300 lb and block B weighs 275 lb determine the required weight of block C and the angle theta for equilibrium?

adoni [48]

Set up a free body diagram.

and by reason, Tcd = Tbd 

Tbd y = 275 - 300*sinθ 
Tcd y = Tc - 300*sin30 

Tbd x = 300*cosθ 
Tcdx = 300 * cos30 

Tbd^2 = (275 - 300*sinθ)^2 + (300*cosθ)^2 
Tcd^2 = (300*sin30)^2 + (300 * cos30)^2 

(275 - 300*sinθ)^2 + (300*cosθ)^2 = (300*sin30)^2 + (300 * cos30)^2 
etc.

5 0

2 years ago

ou are to drive to an interview in another town, at a distance of 300 km on an expressway. The interview is at 11:15 a.m. You pl

Shkiper50 [21]

Answer:

133.62 kmh.

Explanation:

Time provided = 3.25 hours.

Distance to be covered 300 km

Times spent in first 100 km = 1 hour

Time spent in next 43 km

= 43 / 40 = 1.075 hours

Total time spent = 2.075 hours

Total distance covered = 143 km

Distance remaining = 300 - 143

=157 km .

Time remaining = 3.25 - 2.075

= 1.175

Speed required = Distance remaining / time remaining

= 157 / 1.175

= 133.62 kmh.

8 0

3 years ago

A sound wave travels at 379 m/sec and has a wavelength of 8 meters. Calculate its frequency and period.

olga nikolaevna [1]

$\qquad\qquad\huge\underline{{\sf Answer}}$

Wavelength, Wavespeed and frequency depends on each other in the following way :

$\qquad \sf \dashrightarrow \: frequency = \dfrac{wave \: \: velocity}{wavelength}$

$\qquad \sf \dashrightarrow \: f = \dfrac{389}{8}$

$\qquad \sf \dashrightarrow \: f \approx 48.62 \: \: hertz$

And we know the Reciprocal relationship between frequency and period ~

So, let's find it's period •

$\sf{\qquad \sf \dashrightarrow \: t = \dfrac{8}{389}}$

$\sf{\qquad \sf \dashrightarrow \: t \approx 0.02 sec }$

6 0

2 years ago

The bodies in this universe attract one another name the scientist who propounded this statement

murzikaleks [220]

Answer:

It was proposed by Isaac Newton

Explanation:

The law of universal attraction of expression

F = $G \ \frac{m_1m_2}{ r^2}$ G m1m2 / r ^ 2

where G is a constant, m₁ and m₂ are the masses of the bodies and r the distance between them.

It was proposed by Isaac Newton

With this law Newton explained that the force that pulls the moon towards the earth is the same as that which attracts an apple towards the earth

8 0

2 years ago

A chimpanzee sitting against his favorite tree gets up and walks 70.9 m due east and 31.9 m due south to reach a termite mound,

DIA [1.3K]

A right triangle is formed by the 70.9 m walked east and 31.9 m walked south.
The legs of this right triangle are 70.9 and 31.9.
The shortest distance between two points is a straaight line. Therefore the hypotenuse of this triangle is going to be that shortest distance.
We can use the Pythagorean Theorem to find the hypotenuse of this triangle.
$a^2+b^2=c^2\\70.9^2+31.9^2=c^2\\5026.81+1017.61=c^2\\6044.42=c^2\\c=\sqrt{6044.42}$

$c=\sqrt{6044.42}\approx\boxed{77.7458681}\ (decimal\ form)\\\\c=\sqrt{6044.42}=\sqrt{\frac{604442}{100}}=\boxed{\frac{\sqrt{604442}}{10}}\ (exact\ form)$

As for the second part of the question, we want to find the angle formed by the hypotenuse and the 31.9 walked east.
We could use any of the three trigonometric ratios here since we know all 3 sides.
sine = opposite / hypotenuse
cosine = adjacent / hypotenuse
tangent = opposite / adjacent
I am going to use tangent, because then I won't have to deal with the hypotenuse and so the answer will be more accurate.

If you haven't already drawn yourself a diagram, now is a good time to.
The side opposite our angle is the 31.9, and the adjacent is 70.9.
Therefore, $\tan(m\angle)=\frac{31.9}{70.9}$ .

We can use inverse trig ratios here to find the measure of our angle.
$\tan^{-1}(\tan(m\angle))=\tan^{-1}(\frac{31.9}{70.9})\\\\m\angle=\tan^{-1}(\frac{31.9}{70.9})\approx\boxed{24.2243851\°\ or\ 0.422795279\ rad}$

4 0

2 years ago