(a) The total momentum of the system before the train cars collide is 1,600 kgm/s.
(b) The total momentum of the system be after the train cars collide is 1,600 kgm/s.
<h3>What is the total momentum of the car system before the collision?</h3>
The total momentum of the car system before the collision is determined by applying the formula for linear momentum.
Pi = m₁u₁ + m₂u₂
where;
- m₁ is the mass of the car on the right
- m₂ is the mass of the car on the left
- u₁ is the initial velocity of the right
- u₂ is the initial velocity of the car on the left
Let the rightward direction = positive
Let the leftward direction = negative
Pi = (600 kg x 4 m/s) + (400 kg) x (-2 m/s)
Pi = 2,400 kgm/s - 800 kgm/s
Pi = 1,600 kgm/s
Based on the law of conservation of linear momentum, the sum of the initial momentum of an isolated system is <u>equal</u> to the sum of the final momentum of the system
Pf = Pi = 1,600 kgm/s.
Learn more about conservation of linear momentum here: brainly.com/question/7538238
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It's called condensation. That is what that wetness on the outside of the cup is.
Answer:
Yes, dimensionally the equation is correct.
Explanation:
This equation is the kinematic equation for uniformly accelerated motion, then we study the units of each member to conclude whether it is dimensionally correct.
vi = initial velocity [m/s]
a = acceleration [m/s^2]
t = time [s]
v = final velocity
therefore we have:
[m/s] + [m/s^2]*[t^2], the second term now is m/s
[m/s] + [m/s] = [m/s]
So the analysis is correct.
Answer:
(A) As it moves farther and farther from Q, its speed will keep increasing.
Explanation:
When a positive charge Q is fixed on a horizontal frictionless tabletop and a second charge q is released near to it then according to the Coulombs law the force acting on it decreases with the square of the distance between them.
Mathematically:
where:
r = distance between the charges
permittivity of free space
By the Newtons' second law of motion if the we know that the acceleration is directly proportional to the force applied. So as the distance between the charges increases the its acceleration also decreases therefore now the charge feels less acceleration but still continues to accelerate with a fading magnitude.