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astra-53 [7]
3 years ago
9

A block of mass 0.245 kg is placed on top of a light, vertical spring of force constant 4 975 N/m and pushed downward so that th

e spring is compressed by 0.103 m. After the block is released from rest, it travels upward and then leaves the spring. To what maximum height above the point of release does it rise? (Round your answer to two decimal places.)
Physics
1 answer:
FromTheMoon [43]3 years ago
6 0

Answer:

10.99 m

Explanation:

m = mass of the block = 0.245 kg

k = spring constant of the vertical spring = 4975 N/m

x = compression of the spring = 0.103 m

h = height to which the block rise

Using conservation of energy

Potential energy gained by the block = Spring potential energy

mgh = (0.5) k x²

(0.245) (9.8) h = (0.5) (4975) (0.103)²

h = 10.99 m

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Answer:

6858.5712 m/s

Explanation:

Given that:

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Normal force = 0.5 * normal weight

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Fn = 0.5Fg

Recall:

mv² / R = Fn + Fg

Fn = 0.5Fg

mv² / R = 0.5Fg + Fg

mv² /R = 1.5Fg

mv² = 1.5Fg * R

F = mg

mv² = 1.5* mg * R

v² = 1.5gR

v = sqrt(1.5gR)

V = sqrt(1.5 * 9.8 * 3.2 * 10^3)

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<h3>Error percentage in measuring the volume of the cylinder</h3>

The total error percentage in measuring the volume of the cylinder is calculated as follows;

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Learn more about percentage error here: brainly.com/question/5493941

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2 years ago
The cost of energy delivered to residences by electrical transmission varies from $0.070/kWh to $0.258/kWh throughout the United
tankabanditka [31]

Answer:

(a) $ 1.48

(b) $ 0.005

(c) $ 0.38

Explanation:

(a)

First, we calculate the energy consumed, by using following formula:

E = Pt

where,

E = Energy Consumed = ?

P = Power Delivered = (40 W)(1 KW/1000 W) = 0.04 KW

t = Time Duration = (2 weeks)(7 days/week)(24 h/day) = 336 h

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Now, we calculate cost, by following formula:

Cost = (E)(Unit Price)

Cost = (13.44 KWh)($ 0.11/KWh)

<u>Cost = $ 1.48</u>

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(b)

First, we calculate the energy consumed, by using following formula:

E = Pt

where,

E = Energy Consumed = ?

P = Power Delivered = (970 W)(1 KW/1000 W) = 0.97 KW

t = Time Duration = (3 min)(1 h/60 min) = 0.05 h

Therefore,  

E = (0.97 KW)(0.05 h) = 0.0485 KWh

Now, we calculate cost, by following formula:

Cost = (E)(Unit Price)

Cost = (0.0485 KWh)($ 0.11/KWh)

<u>Cost = $ 0.005</u>

<u></u>

(c)

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E = Pt

where,

E = Energy Consumed = ?

P = Power Delivered = (5.203 x 10³ W)(1 KW/1000 W) = 5.203 KW

t = Time Duration = (40 min)(1 h/60 min) = 0.67 h

Therefore,  

E = (5.203 KW)(0.67 h) = 3.47 KWh

Now, we calculate cost, by following formula:

Cost = (E)(Unit Price)

Cost = (3.47 KWh)($ 0.11/KWh)

<u>Cost = $ 0.38</u>

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