1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
alukav5142 [94]
3 years ago
13

The gases cast off by a dying star are called

Physics
2 answers:
Nady [450]3 years ago
7 0

Answer:

Planetary Nebula

Explanation:

A star has its own life cycle very similar to a human life cycle where it takes birth, grows up, becomes old and then dies. The life cycle of stars and human differ in the duration of cycle and end result.

When a star dies it can end up differently basis its mass. Here one of the ends of a star is mentioned where it casts off all the gases. Such type of situation will create a planetary nebula. One famous example of such nebula is Crab Nebula.

lozanna [386]3 years ago
4 0
Planetary Nebulae hope that helps
You might be interested in
A body moving in the positive x direction passes the origin at time t = 0. Between t=0 and t=1 second, the body has a constant s
lord [1]

The important thing in this type of questions is to keep track of what you are doing at every point.

From t=0 to t=1s, there is uniform motion at v=24 m/s.

Therefore, it will move 24m in that second of time.

Afterwards, an acceleration comes in, so from t=1s to 11s there will be uniformly accelerated motion with acceleration -6m/s^2.

To account for this, you need to use Suvat's equation:

x(t)=x0+v0*t+1/2*a*t^2.

You should know what to plug in for each of the symbols in this equation:

x0 [initial position at t=1s] = 24m

v0 [initial velocity at t=1s] = 24 m/s

a [acceleration, switched on at t=1s] = -6 m/s^2

t [time from the start of the acceleration until the end, i.e. from t=1s to t=11s] = 10s

Plugging in those numbers in the equation will give you the position at t=11s.

4 0
3 years ago
Read 2 more answers
A 2.00 kg cat is in a 97.00 kg elevator. What force on the elevator cable would be needed to lower the cat/elevator pair with an
umka21 [38]

The magnitude of force on the elevator cable that would be needed to lower the cat/elevator pair is 198 Newton.

<u>Given the following data:</u>

  • Mass of cat = 2 kg
  • Mass of elevator = 97 kg
  • Acceleration = 2 m/s^2

To determine the magnitude of force on the elevator cable that would be needed to lower the cat/elevator pair, we would apply Newton's Second Law of Motion:

First of all, we would calculate the total mass of the cat/elevator pair.

Total \;mass=2 + 97

Total mass = 99 kilograms

Mathematically, Newton's Second Law of Motion is given by this formula;

Force = mass \times acceleration

Substituting the given parameters into the formula, we have;

Force = 99 \times 2

Net force = 198 Newton

Read more here: brainly.com/question/24029674

3 0
2 years ago
You have a length of tubing that is closed at one end. You cut the tubing into two pieces of unequal length, giving you a tube o
umka21 [38]

Answer:

The funda mental frequency of the original tube is 182Hz.

Explanation:

See the attachment for the calculation steps.

In order to calculate the fundamental frequency of the original closed tube we need to find the length of the tube which is equal to the sum of the lengths of the two new tubes.

For closed tubes

f = nv/4L (n = 1, 3, 5,...n)

f = nv/2L (n = 1, 2, 3,...n)

The details of calculation can be found below in the attachment.

4 0
3 years ago
More people end up in U.S. emergency rooms because of fall-related injuries than from any other cause. At what speed v would som
miss Akunina [59]

Answer:

v_{f}=6.47m/s

Explanation:

Given data

Distance d=7.00 ft= 7*(1/3.281) =2.1336m

Initial velocity vi=0m/s

To find

Final velocity

Solution

From Kinematic equation we know that:

v_{f}^{2} =v_{i}^{2}+2gd\\v_{f}^{2}=0+2(9.81m/s^{2} ) (2.1336m)\\v_{f}^{2}=41.86\\v_{f}=\sqrt{41.86}\\v_{f}=6.47m/s

6 0
3 years ago
A car of mass 998 kilograms moving in the positive y–axis at a speed of
aksik [14]
The total momentum should come out to be  <span>2.0 x 10^4 kilogram meters/second </span>
8 0
3 years ago
Read 2 more answers
Other questions:
  • Suppose for an unexplained reason a star near Earth started shrinking. At what stage is the gravitational force between Earth an
    15·2 answers
  • Consider a steel guitar string of initial length l=1.00m and cross-sectional area a=0.500mm2. the young's modulus of the steel i
    7·1 answer
  • A feeding buffer protects ______ path from delays in ______ ____.
    11·1 answer
  • A stationary source S generates circular outgoing waves on a lake. The wave speed is 5.0 m/s and the crest-to-crest distance is
    9·1 answer
  • 10Ω resistor and a 5 Ω are connected in parallel. This pair is then connected in series in with another 4 Ω resistor. What is th
    14·1 answer
  • A man walks 30 meters north,then 90 meters east, and then 30 meters south​
    11·1 answer
  • Assertion: When I P+ Q I = I P- QI, then P must be perpendicular to Q. Reason: The relation will hold even when Q is a null vect
    7·1 answer
  • The scanning process and magnetic lenses used in a scanning electron microscope often results in fair to poor resolution and "fu
    5·1 answer
  • The distance from the sun to Earth would be
    7·1 answer
  • Am object of mass in a circular path of radius 100metres with the speed of 10metres/second.calculate the acceleration towards th
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!