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Snezhnost [94]
2 years ago
6

Coherent light with wavelength 540 nm passes through narrow slits with a separation of 0.370 mm .Part AAt a distance from the sl

its which is large compared to their separation, what is the phase difference (in radians) in the light from the two slits at an angle of 25.0 ∘ from the centerline?
Physics
1 answer:
77julia77 [94]2 years ago
5 0

Answer:

The phase difference between waves 31.7 rad

Explanation:

Given :

Wavelength \lambda = 540 \times 10^{-9} m

Separation between two slit d = 0.370 \times 10^{-3} m

Angle \theta = 25°

From the formula of phase difference,

  \delta = \frac{2\pi d }{\lambda}  \sin \theta

Where \delta = phase difference

\delta = \frac{2 \times \pi \times 0.370 \times 10^{-3} }{540 \times 10^{-9} } \sin 25

\delta = 31.7 rad

Therefore, the phase difference between waves 31.7 rad

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1000 kgm²/s, 1000 J

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The rotational energy of the system is 400 J

There no external toque present so the initial and final angular momentum will be equal to the initial angular momentum 1000 kgm²/s

L_i=L_f\\\Rightarrow 2mv_ir_i=2mv_fr_f\\\Rightarrow v_f=\frac{v_ir_i}{r_f}\\\Rightarrow v_f=\frac{2\times 2.5}{0.5}\\\Rightarrow v_f=10\ m/s

Energy

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The work done is 600 J

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