Question

Coherent light with wavelength 540 nm passes through narrow slits with a separation of 0.370 mm .Part AAt a distance from the slits which is large compared to their separation, what is the phase difference (in radians) in the light from the two slits at an angle of 25.0 ∘ from the centerline?

Answer 1

Answer:

The phase difference between waves 31.7 rad

Explanation:

Given :

Wavelength $\lambda = 540 \times 10^{-9}$ m

Separation between two slit $d = 0.370 \times 10^{-3}$ m

Angle $\theta =$ 25°

From the formula of phase difference,

  $\delta = \frac{2\pi d }{\lambda} \sin \theta$

Where $\delta =$ phase difference

$\delta = \frac{2 \times \pi \times 0.370 \times 10^{-3} }{540 \times 10^{-9} } \sin 25$

$\delta = 31.7$ rad

Therefore, the phase difference between waves 31.7 rad