Answer:
(a) Force must be grater than 283.87 N
(B) Force will be equal to 193.945 N
Explanation:
We have given mass of the crate m = 49.6 kg
Acceleration due to gravity ![g=9.8m/sec^2](https://tex.z-dn.net/?f=g%3D9.8m%2Fsec%5E2)
Coefficient of static friction ![\mu _s=0.584](https://tex.z-dn.net/?f=%5Cmu%20_s%3D0.584)
Coefficient of kinetic friction ![\mu _k=0.399](https://tex.z-dn.net/?f=%5Cmu%20_k%3D0.399)
(a) Static friction force is given by ![F_S=\mu _smg=0.584\times 49.6\times 9.8=283.8707N](https://tex.z-dn.net/?f=F_S%3D%5Cmu%20_smg%3D0.584%5Ctimes%2049.6%5Ctimes%209.8%3D283.8707N)
So to just start the crate moving we have to apply more force than 283.87 N
(B) This force will be equal to kinetic friction force
We know that kinetic friction force is given by ![F_k=\mu _kmg=0.399\times 49.6\times 9.8=193.945N](https://tex.z-dn.net/?f=F_k%3D%5Cmu%20_kmg%3D0.399%5Ctimes%2049.6%5Ctimes%209.8%3D193.945N)
Answer:
The electromagnetic force
Explanation:
There are four fundamental forces in nature:
- Gravitational force: it is the force that acts between any particles having mass. It is relevant only on very large scales (planets, stars), since it is the weakest of the 4 forces, so very large masses are needed in order to produce relevant effects.
- Electromagnetic force: it is the force that acts between particles with electric charge. It can be attractive or repulsive. It is the main force that acts between atoms and molecules.
- Strong nuclear force: it is the force that keeps the protons and the neutrons together inside the nucleus. It acts only on very short scales (only within the nucleus of the atom)
- Weak nuclear force: it is the force responsible for the radioactive decays of certain nuclei. It also acts on very short scales.
Therefore, the force that is responsible for binding atoms together to form molecules is the electromagnetic force.
3 protons should be your answer
Answer:
1000 N
Explanation:
The magnitude of the electrostatic force between two charged object is given by
![F=k\frac{q_1 q_2}{r^2}](https://tex.z-dn.net/?f=F%3Dk%5Cfrac%7Bq_1%20q_2%7D%7Br%5E2%7D)
where
k is the Coulomb constant
q1, q2 is the magnitude of the two charges
r is the distance between the two objects
Moreover, the force is:
- Attractive if the two forces have opposite sign
- Repulsive if the two forces have same sign
In this problem:
are the two charges
r = 3000 m is their separation
Therefore, the electric force between the charges is:
![F=(9\cdot 10^9)\frac{(1)(1)}{3000^2}=1000 N](https://tex.z-dn.net/?f=F%3D%289%5Ccdot%2010%5E9%29%5Cfrac%7B%281%29%281%29%7D%7B3000%5E2%7D%3D1000%20N)
Answer:F=4F
Explanation: Columbs law states that The force between the two point charges is directly proportional to the product of charges and inversely proportional to the square of distance between them
Force between the two charges is given by
F=K*q1*q2/r^2
if one charge become 4 times, new force is,
F=4(K*q1*q2)/r^2
F=4F
Where q1 and q2 are the point charges
r is the distance between the two charges
K is a constant of proportion called electrostatic force