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attashe74 [19]
2 years ago
6

How much heat energy would be needed to raise the temperature of a 223 g sample of aluminum [(C=0.895 Jig Cy from 22.5°C to 55 0

°C? Η Ο Ο Ο ΟΟ 10x10) not enough information given Prov 40 25 11 Next >
Chemistry
1 answer:
dsp732 years ago
5 0

Answer : The heat energy needed would be, 6486.5125 J

Explanation :

To calculate the change in temperature, we use the equation:

q=mc\Delta T\\\\q=mc(T_2-T_1)

where,

q = heat needed = ?

m = mass of aluminum = 223 g

c = specific heat capacity of aluminum = 0.895J/g^oC

\Delta T = change in temperature

T_1 = initial temperature = 22.5^oC

T_2 = final temperature = 55.0^oC

Putting values in above equation, we get:

q=223g\times 0.895J/g^oC\times (55.0-22.5)^oC

q=6486.5125J

Therefore, the heat energy needed would be, 6486.5125 J

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Answer: 5

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3 years ago
The equilibrium constant Kc for the reaction below is 0.00584 at a certain temperature. Br2(g) ⇌ 2Br(g) If the initial concentra
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Answer:

Explanation:

Given that:

The chemical equation for the reaction is:

             Br2(g)    ⇌  2Br(g)

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Q_C = \dfrac{[Br]^2}{[Br_2]} = \dfrac{(0.0416)^2}{(0.0345)}= 0.05016

Q_C =0.05016 >>> K_c(0.00584)

Thus, the given reaction will proceed in the  backward direction

 The I.C.E table is as follows:

                       Br2(g)    ⇌  2Br(g)

I               0.0345                 0.0416

C                 +x                        -2x

E             (0.0345+x)            (0.0416 -2x)

K_c = \dfrac{[Br]^2}{[Br_2]} = \dfrac{(0.0416-2x)^2}{(0.0345+x)} = 0.00584

= 0.00173056 - 0.0832x - 0.0832x + 4x² = 0.00584 (0.0345 +x)

= 0.00173056 - 0.166x + 4x² = 2.0148× 10⁻⁴ + 0.00584x

= 0.00173056 - 2.0148× 10⁻⁴ - 0.166x - 0.00584x + 4x²

= 0.00152908  - 0.17184x + 4x²

Solving by using Quadratic formula

x = 0.03038 or 0.0126

For x = 0.03038

At equilibrium

[Br₂] = (0.0345 + 0.03038) = 0.06488 M

[Br] =  (0.0416 -2(0.03038)) = - 0.01916 M

Since we have a negative value for [Br], we discard the value for x

For x = 0.0126

At equilibrium

[Br₂] = (0.0345 + 0.0126) = 0.0471 M

[Br] =  (0.0416 -2(0.0126)) = 0.0164 M

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The new volume : 0.07 L

<h3>Further explanation</h3>

Boyle's Law  

At a constant temperature, the gas volume is inversely proportional to the pressure applied  

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3 years ago
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