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butalik [34]
3 years ago
15

A force of 10.0 N is applied to a 6.0 kg obiect to move it across a smooth surface. The surface is frictionless. Draw and level

all the forces, Calculate the acceleration of the object.
Physics
1 answer:
ch4aika [34]3 years ago
4 0

Answer:

Acceleration, a=1.66\ m/s^2

Explanation:

It is given that,

Force acting on the object across a smooth surface, F = 10 N

Mass of the object, m = 6 kg

Let a is the acceleration of the object. The forces acting on teh object is given by :

F = ma

a=\dfrac{F}{m}

a=\dfrac{10\ N}{6\ kg}

a=1.66\ m/s^2

So, the acceleration of the object is 1.66\ m/s^2. Hence, this is required solution.

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A fluid has a density of 921 kg/m^3. at a depth of 1.22 m, the fluid pressure is 122,000 Pa. what is the pressure at the top of
Igoryamba

Answer:

111,000 Pa

Explanation:

P = Patm + ρgh

122,000 Pa = Patm + (921 kg/m³) (9.8 m/s²) (1.22 m)

Patm = 111,000 Pa

3 0
3 years ago
Two cars are travelling side by side down a straight road in the same direction. Both cars are travelling at a speed of 22m/s. W
ivann1987 [24]

Answer:

0 m/s

Explanation:

Relative speed is defined as the speed of an object with respect with another object.

In other words, it is the speed of an object as viewed from the frame of reference of another object.

When two objects are moving in the same direction, their relative velocity is given as:

V_{12} = V_1 - V_2

where V_1 = velocity of first object

V_2 = velocity of second object

In the case of the two cars, V_1 = V_2 = 22 m/s

Therefore:

V_{12} = 22 - 22 = 0 m/s

Their relative velocity is 0 m/s.

3 0
3 years ago
Read 2 more answers
If μs is greater than some critical value, the woman cannot start the crate moving no matter how hard she pushes. calculate this
fiasKO [112]

weight = mg acts downwards <span>
normal force = N acts upwards. 
and force F acts at an angle θ below the horizontal. 
(Let us assume that the woman pushes from the left, so F is acted towards the right, which is below the horizontal) 
so that, Frictional force, f=us*N acts towards the left 

Now we balance the forces along x and y directions: 
y direction: N = mg + F sinΘ 
x direction: us * N = F cosΘ 

We let the value of µs be equal to a value such that any F will not be able to move the crate. Then, if we increase F by an amount F', then the force pushing the crate towards the right also increases by F' cosΘ. Additionally, the frictional force f must raise by exactly this amount. 
Since f can’t exceed us*N, so the normal force must increase by F' cosΘ/us. 
Also, from the y direction equation, the normal force exceeds by F' sin Θ. 

<span>These two values must be the same, therefore:
<span>us = cot θ</span></span></span>

4 0
3 years ago
wo plates with area 6.00×10−3 m2 are separated by a distance of 1.50×10−4 m . If a charge of 5.40×10−8 C is moved from one plate
liq [111]

Answer:

V = 152.542 volts

Explanation:

Given data:

area of plates6.00\times 10^{-3} m^2

distance between the plates is 1.50\times 10^{-4} m

charge = 5.40\times 10^{-8} c

we know that capacitance is given as

C = \frac{\epsilon A}{d}

C = \frac{8.85\times 10^{-12} 6\times 10^{-3}}{1.50\times 10^{-4}}

C = 3.54\times 10^{-10} F

potential difference is given as

V =\frac{Q}{C} = \frac{5.40\times 10^{-8}}{3.54\times 10^{-10}}

V = 152.542 volts

3 0
3 years ago
Fill in the blank .Technically color consists of electromagnetic _____
8_murik_8 [283]
Electromagnetic radiation
5 0
3 years ago
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