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3 years ago

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A force of 10.0 N is applied to a 6.0 kg obiect to move it across a smooth surface. The surface is frictionless. Draw and level

all the forces, Calculate the acceleration of the object.

1 answer:

ch4aika [34]3 years ago

4 0

Answer:

Acceleration, $a=1.66\ m/s^2$

Explanation:

It is given that,

Force acting on the object across a smooth surface, F = 10 N

Mass of the object, m = 6 kg

Let a is the acceleration of the object. The forces acting on teh object is given by :

F = ma

$a=\dfrac{F}{m}$

$a=\dfrac{10\ N}{6\ kg}$

$a=1.66\ m/s^2$

So, the acceleration of the object is $1.66\ m/s^2$ . Hence, this is required solution.

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A concave spherical mirror has a radius of curvature of magnitude 20.0 cm. (a) Find the location of the image for object distanc

Tems11 [23]

Answer:

Answered

Explanation:

The radius of curvature of the mirror R = 20 cm

then the focal length f = R/2 = 10 cm

(a) From mirror formula

1/f = 1/di + /1do

then the image distance

di = fd_o / d_o - f

= (10)(40) / 40-10

= 30.76 cm

since the image distance is positive so the image is real

ii) when the object distance d_0=20 cm

di = 10×20/ 20-10

= 20

Hence, the image must be real

iii)when the object distance d_0 = 10

di = 10×10 / 10-10 = ∞ (infinite)

the image will be formed at ∞

here also image will be real but diminished.

7 0

2 years ago

Read 2 more answers

A multimeter in an RL circuit records an rms current of 0.600 A and a 50.0-Hz rms generator voltage of 110 V. A wattmeter shows

jeka57 [31]

Answer:

(a) The impedance in the circuit is $Z=183.33\Omega$ .

(b)The resistance is $R=38.89\Omega$ .

(c) The inuctance is 0.57 H.

Explanation:

(a)

The expression for the impedance is as follows:

$Z=\frac{V_rms}{I_rms}$

Here, $V_rms$ is the rms voltage and $I_rms$ is the rms current.

Put $V_rms=110 V$ and $I_rms=0.600 A$ .

$Z=\frac{110}{0.600}$

$Z=183.33\Omega$

Therefore, the impedance in the circuit is $Z=183.33\Omega$ .

(b)

The expression for the average power is as follows;

$P_{a}=I_{rms}^{2}R$

Here, $P_{a}$ is the average power and R is the resistance.

Calculate the resistance by rearranging the above expression.

$R=\frac{P_{a}}{I_{rms}^{2}}$

Put $P_{a}=14W$ and

$R=\frac{14}{{0.600}^{2}}$

$R=38.89\Omega$

Therefore, the resistance is $R=38.89\Omega$ .

(c)

The expression for the impedance is as follows;

$Z^{2}=R^{2}+X_{L}^{2}$

Here, $X_{L}$ is the inductive reactance.

Put $Z=183.33\Omega$ and $R=38.89\Omega$ .

$(183.33)^{2}=(38.89)^{2}+X_{L}^{2}$

$X_{L}=179.16\Omega$

The expression for the inductive reactance in terms of frequency is as follows;

$X_{L}=2\pi fL$

Here, L is the inductance.

Calculate the inductance by rearranging the above expression.

$L=\frac{X_{L}}{2\pi f}$

Put $X_{L}=179.16\Omega$ and f=50Hz.

$L=\frac{179.16}{2\pi (50)}$

L=0.57 H

Therefore, the inuctance is 0.57 H.

4 0

2 years ago

someone help me please haha Calculate the braking force of a lorry decelerating at a rate of 8 m/s² with a mass of 5000 kg.

ICE Princess25 [194]

Answer:

40000 N

Explanation:

Force: This cam be defined as the product of mass and acceleration.

From the question,

The braking force of the lorry will be the same in magnitude as the force at which the lorry is moving.

F = ma..................... Equation 1

Where m = mass of the lorry, a = acceleration/deceleration of the lorry.

Given: m = 5000 kg, a = 8 m/s²

Substitute these values into equation 1

F = 5000(8)

F = 40000 N

6 0

3 years ago

A satellite orbiting Earth at a velocity of 3700 m/s collides with a piece of

Gekata [30.6K]

Answer: B

Explanation:

You can use the conservation of momentum, under the assumption that no mass was lost when the collision occurred. The initial momentum of the system must equal the final momentum of the system. Our system is the region including, and only including, the satellite and the space debris. Classical momentum is defined as the product of mass and velocity:

$p_i=p_f$

$m_1v_1_i+m_2v_2_i=m_1v_1_f+m_2v_2_f$

Due to mass 1 equaling mass 2, we can factor these quantities out:

$m(v_1_i+v_2_i)=m(v_1_f+v_2_f)$

Cancel the mass term on both sides to get:

$v_1_i+v_2_i=v_1_f+v_2_f$

We have the initial and final velocities for everything besides the final velocity of the satellite. Plug everything in:

$3700m/s+6000m/s=v_1_f+3700m/s$

$v_1_f=6000m/s$

7 0

1 year ago

A force of 8,480 N is applied to a cart to accelerate it at a rate of 26.5 m/s2. What is the mass of the cart?

katrin2010 [14]

Answer:

<h2>320</h2>

Just use F =ma where m is mass and a is acc.

8 0

2 years ago