Answer:
367.04 N
Explanation:
Frictional force = mass of the toboggan×deceleration caused by the rough region
Fr = m×ar....................... Equation 1
Where Fr = Average frictional force, m = mass of loaded toboggan, ar = deceleration cause by the rough region.
We can calculate for ar using the formula below
v² = u²+2ars................... Equation 2
make ar the subject of the equation
ar = (v²-u²)/2s.................. Equation 3
Where v = final velocity of the toboggan, u = initial velocity of the toboggan, s = distance or length of the rough region
Given: v = 1.2 m/s, u = 4.6 m/s, s = 8.6 m
Substitute into equation 3
ar = (1.2²-4.6²)/(2×8.6)
ar = (1.44-21.16)/17.2
ar = -19.72/17.2
ar = -1.147 m/s²
Also given: m = 320 kg
Substitute into equation 1
Fr = 320(-1.147)
Fr = -367.04 N
Note: The negative sign tells that the frictional force opposes the motion of the toboggan
