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3 years ago

The combined gas law does not account for changes in _____.

2 answers:

8 0

The combined gas law does not account for changes in power. The combined gas law has no official founder; it is simply the incorporation of the three laws that was discovered. The combined gas law is a gas law that combines Gay-Lussac’s Law, Boyle’s Law and Charle’s Law. Boyle’s law states that pressure is inversely proportional with volume at constant temperature. Charle’s law states that volume is directly proportional with temperature at constant pressure. And Gay-Lussac’s law shows that pressure is directly proportional with temperature at constant volume. The combination of these laws known now as combined gas law gives the ratio between the product of pressure-volume and the temperature of the system is constant. Which gives PV/T=k(constant). When comparing a substance under different conditions, the combined gas law becomes P1V1/T1 = P2V2/T2.

vitfil [10]3 years ago

8 0

d temperature is the correct answer

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An automobile accelerates uniformly from a speed of 60 km/hr (16.67 m/s) to a speed of 80 km/hr (22.2 m/s) in 5 s. Determine the

monitta

Answer:

The acceleration is $1.106\ m/s^2$ and the distance covered is 97.17 m.

Explanation:

Given that,

Initial speed of an automobile, u = 60 km/hr = 16.67 m/s

Final speed of an automobile, v = 80 km/hr = 22.2 m/s

Time, t = 5 s

We need to find the acceleration of the car and the distance traveled in this 5 sec interval. Let a is the acceleration. Using the definition of acceleration as :

$a=\dfrac{v-u}{t}\\\\a=\dfrac{22.2-16.67}{5}\\\\a=1.106\ m/s^2$

Let d is the distance covered. Using the third equation of motion to find it as follows :

$v^2-u^2=2as\\\\s=\dfrac{v^2-u^2}{2a}\\\\s=\dfrac{(22.2)^2-(16.67)^2}{2\times 1.106}\\\\s=97.17\ m$

So, the acceleration is $1.106\ m/s^2$ and the distance covered is 97.17 m.

7 0

3 years ago

Find the value of x in this figure

liraira [26]

Answer:

x=50

Explanation:

6 0

3 years ago

Read 2 more answers

What is the correct water depth for an echo travel time of 6 seconds? (for the purposes of this exercise, assume pressure and te

saul85 [17]

In physics, there are empirical values for common important parameters. For example, the speed of sound is equal to 340 meters per second. Unlike the speed of light, the speed of sound is dependent on temperature and pressure. But in standard room conditions, the speed is 340 m/s. Using this value of speed, we can find the depth given the time. You should also note that the distance the echo travels is exactly the same distance that object travelled. Therefore,

Distance = 340 m/s * 6 seconds
Distance = 2,040 meters deep

7 0

4 years ago

Density of salty water as compared to the density of pure water is

sweet-ann [11.9K]

The answer of this question is (c) is always more

4 0

3 years ago

A wire delivers 120 C of charge in 40 s.

Neporo4naja [7]

Answer:

3 A

Explanation:

Charge is a product of current and time, expressed as Q=It where Q is charge in Coulombs, I is current in Amperes and t is time taken in seconds. Making I the subject of the formula then $I=\frac {Q}{t}$

Substituting 120 C for charge and 40 s for t then $I=\frac {120}{40}=3\ A$

From the choices given, it appears that time should have been 4 s to get option A or alternatively charge should have been 1200 C

3 0

3 years ago