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marishachu [46]
3 years ago
7

A circuit has a source voltage of 15V and two resistors in series with a total resistance of 4000Ω .If RI has a potential drop o

f 9.375 V across it, what is the value of R2? (a) 2000Ω (b) 1500Ω (c) 1000Ω (d) 500Ω
Engineering
1 answer:
anastassius [24]3 years ago
6 0

Answer:

1500Ω

Explanation:

Given data

voltage = 15 V

total Resistance = 4000Ω

potential drop V = 9.375 V

To find out

R2

Solution

we know R1 +R2 = 4000Ω

So we use here Ohm's law to find out current I

current = voltage / total resistance

I = 15 / 4000 = 3.75 × 10^{-3} A

Now we apply Kirchhoffs Voltage Law for find out R2

R2 = ( 15 - V ) / current

R2 = ( 15 - 9.375 ) / 3.75 × 10^{-3}

R2 = 1500Ω

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Answer:

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Explanation:

given data

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to find out

what is the difference in pressure between the inside and outside of the droplets

solution

we know here surface tension of carbon tetra chloride at 68 °F is get from table 1.6 physical properties of liquid that is

σ = 2.69 × 10^{-2} N/m

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now here we know relation between pressure difference and surface tension

so we can derive difference pressure as

2π×σ×r = Δp×π×r²    .....................1

here r is radius and  Δp pressure difference and σ surface tension

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put here value

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Δp = 538

so the difference in pressure between the inside and outside of the droplets is 538 Pa

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Answer:

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Answer:

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