Ask question

Ask question

All categories

2 years ago

7

The gas in a balloon has T=280K and V=0.0279m^3. If the temperature increases to 320K at constant pressure, what is the new volu

me of the balloon? (Hint: n and P are constant) (Unit= m^3)

1 answer:

photoshop1234 [79]2 years ago

7 0

Answer:

$\boxed{ V_{2}= 0.03189 m^3}$

Explanation:

According to Charles Law

=> $\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}$

Where $V_{1}$ = 0.0279 m³, $T_{1}$ = 280 K and $T_{2}$ = 320 K

=> $\frac{0.0279}{280} = \frac{V_{2}}{320}$

=> $V_{2}$ = 0.03189 m³

You might be interested in

A rock hits a window and stops in 0.15 seconds. The net force on the rock is 58N during the collision. What is the magnitude of

nlexa [21]

Answer:

The change in momentum is $\Delta p = 0.7 \ kg\cdot m \cdot s^{-1}$

Explanation:

From the question we are told that

The time taken for the stone to stop is $\Delta t = 0.15 \ seconds$

The net force on the rock is $F = 58 \ N$

The impulse of the rock can be mathematically represented as

$I = F * \Delta t$

Substituting values

$I = 58 * 0.15$

$I = 0.7\ kg * m * s^{-1}$

Now impulse is defined as the rate at which momentum change

Hence the change in momentum $\Delta p$ of the rock is equal to the impulse of the rock

So

$\Delta p = I = 0.7 \ kg\cdot m \cdot s^{-1}$

7 0

3 years ago

Two point charges each carrying a charge of + 4.5 E - 6 C are located 4.5 meters away from each other. How strong is the electro

BARSIC [14]

Answer:

0.009 N, repulsive

Explanation:

The electrostatic force between two electric charges is given by:

$F=k\frac{q_1 q_2}{r^2}$

where

k is the Coulomb's constant

q1 and q2 are the two charges

r is the separation between the two charges

In this problem, we have

$q_1 =q_2 = +4.5\cdot 10^{-6}C$ are the two charges

r = 4.5 m is their separation

Substituting into the equation, we find

$F=(9\cdot 10^9 Nm^2 C^{-2})\frac{(+4.5\cdot 10^{-6} C)(4.5\cdot 10^{-6} C)}{(4.5 m)^2}=0.009 N$

Moreover, the force is repulsive. In fact, the following rules apply:

- When two charges have same sign, they repel each other

- When two charges have opposite signs, they attract each other

7 0

2 years ago

A student of weight 652 N rides a steadily rotating Ferris wheel (the student sits upright). At the highest point, the magnitude

miskamm [114]

Answer:

Explanation:

Given

Weight of person $W=652\ N$

At highest point Magnitude of the normal force $F=585\ N$

net force at highest point

$F_{net}=W+F_c$

where $F_c=$ centripetal force

$F_c=\dfrac{mv^2}{r}$

$F_{net}=F_{n}=$ Normal Force

$585=652+F_c$

$F_c=-67\ N$

Negative sign shows force is in upward direction

At bottom point centripetal force is towards the bottom

$F_n=F_c+W$

$F_n=652+67$

$F_n=719\ N$

8 0

3 years ago

A uniform electric field of magnitude 4.6 ✕ 104 N/C is perpendicular to a square sheet with sides 3.0 m long. What is the electr

rodikova [14]

Answer:

41.4* 10^4 N.m^2/C

Explanation:

given:

E= 4.6 * 10^4 N/C

electric field is 4.6 * 10^4 N/C and square sheet is perpendicular to electric field so, area of vector is parallel to electric field

then electric flux = ∫ E*n dA

= ∫ 4.6 * 10^4 * 3*3

= 41.4* 10^4 N.m^2/C

3 0

2 years ago

Read 2 more answers

The cars on an amusement-park ride travel at a constant velocity of 4.0 m/s on a circular track

lys-0071 [83]

V^2=u^2+2as
V=0
a =-u^2/2s
a=[4]^2/2[4]
a=-2m/s^2

7 0

2 years ago