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diamong [38]
3 years ago
7

The gas in a balloon has T=280K and V=0.0279m^3. If the temperature increases to 320K at constant pressure, what is the new volu

me of the balloon? (Hint: n and P are constant) (Unit= m^3)
Physics
1 answer:
photoshop1234 [79]3 years ago
7 0

Answer:

\boxed{ V_{2}= 0.03189 m^3}

Explanation:

According to Charles Law

=> \frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}

Where V_{1} = 0.0279 m³, T_{1} = 280 K and T_{2} = 320 K

=> \frac{0.0279}{280} = \frac{V_{2}}{320}

=> V_{2} = 0.03189 m³

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