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diamong [38]
3 years ago
7

The gas in a balloon has T=280K and V=0.0279m^3. If the temperature increases to 320K at constant pressure, what is the new volu

me of the balloon? (Hint: n and P are constant) (Unit= m^3)
Physics
1 answer:
photoshop1234 [79]3 years ago
7 0

Answer:

\boxed{ V_{2}= 0.03189 m^3}

Explanation:

According to Charles Law

=> \frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}

Where V_{1} = 0.0279 m³, T_{1} = 280 K and T_{2} = 320 K

=> \frac{0.0279}{280} = \frac{V_{2}}{320}

=> V_{2} = 0.03189 m³

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Explanation:

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Give an example of a scientific hypothesis. Explain how you would test it, and how it could be falsified (proved untrue).
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my hypothesis is that If you drop a piece of buttered toast, it will land butter side down.


I tested it by dropping 10 pieces of buttered toast off the table and noted on which side it landed


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If we interpret the large, angular rocks to have originated from the outcrop at the top of the hill, we are using __________ rea
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2 years ago
The free body diagram represents Silly Sally hanging from a trapeze bar. Sally weighs 660 Newtons. What is the force in each of
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7 0
4 years ago
you push with an 18-N horizontal force on a 5-kg box of coffee resting on a on a horizontal surface. the force of friction on th
KatRina [158]

The acceleration is found to be 2 m/s², final velocity after 10 seconds is 20 m/s and the final position after 10 seconds is 100 m away from the starting point.

Answer:

Explanation:

As per Newton's second law of motion, acceleration of any object is directly proportional to the net external unbalanced force acting on that object and inversely proportional to the mass of the object.

Since there are two forces acting on the box in opposite direction, the net force will be the difference of horizontal and frictional force acting on the object.

Net force = Horizontal force - Frictional force = 18 N - 8 N = 10 N.

Now, from second law of motion, Acceleration = \frac{Net force}{Mass}

So, acceleration = 10 N /5 kg = 2 m/s².

Since, acceleration exerted by the box is found to be 2 m/s², we can determine the final velocity of the object after 10 seconds using the first equation of motion.

v = u + at, Here v is the final velocity and u is the initial velocity which is zero for the present case. Other parameters like a is found to be 2 m/s² and time is 10 seconds.

So Final velocity v = 0+(2×10)=20 m/s.

And the final position can be determined using the second equation of motion.

s = ut+1/2at²

Final position = (0×10)+(0.5×2×10×10)= 100 m.

So the final position is 100 m.

Thus, the acceleration is found to be 2 m/s², final velocity after 10 seconds is 20 m/s and the final position after 10 seconds is 100 m away from the starting point.

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3 years ago
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