Question

The gas in a balloon has T=280K and V=0.0279m^3. If the temperature increases to 320K at constant pressure, what is the new volume of the balloon? (Hint: n and P are constant) (Unit= m^3)

Answer 1

Answer:

$\boxed{ V_{2}= 0.03189 m^3}$

Explanation:

According to Charles Law

=> $\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}$

Where $V_{1}$ = 0.0279 m³, $T_{1}$ = 280 K and $T_{2}$ = 320 K

=> $\frac{0.0279}{280} = \frac{V_{2}}{320}$

=> $V_{2}$ = 0.03189 m³