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jek_recluse [69]
4 years ago
9

If a beaker of water and a beaker of acetic acid are at the same elevated temperature, which will cool more quickly to room temp

erature? Support your answer.
Chemistry
1 answer:
4vir4ik [10]4 years ago
4 0
The beaker of acetic acid will cool more quickly.

The specific heat capacity of acetic acid is about half that of water.
Thus, it takes twice as much heat gain (or loss) in acetic acid to cause a given change in temperature.
If everything else is constant and heat is being lost at the same rate, the temperature of the acetic acid should drop twice as fast as that of water.
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Forensic biologist Manning is looking at a cell sample under the microscope. The cell she sees is oval, with a long tail or flag
Gre4nikov [31]

Answer:

Sperm Cell

Explanation:

8 0
3 years ago
What is the last element in the periodic table?
borishaifa [10]

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Ununoctium

Explanation:

It's at the very end of the periodic table

6 0
3 years ago
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The reaction 2Mg(s) + O2(g) --> 2MgO(s) is a
liq [111]

Answer:

Double-Replacement Reaction

Explanation:

Mg is Oxidized, and O2 is the cause of the oxidation, hence the Oxidizing agent.  That means that O2 is Reduced and Mg is the cause naming it the Reducing agent.

OIL - RIG   Oxidation is Loss-Reduction is Gain

6 0
3 years ago
86.1 g of nitrogen reacts with lithium, how many grams of lithium will react?
Zina [86]

Answer:

128g of Li, will react in this reaction

Explanation:

Before to start working, we need the reaction:

N₂ and Li react, in order to produce Li₃N (lithium nitride)

N₂ + 6Li → 2Li₃N

1 mol of nitrogen reacts with 6 moles of lithium

We convert the mass of N₂ to moles → 86.1 g . 1 mol/ 28g = 3.075 moles

1 mol of N₂ reacts with 6 mol of Li

Therefore, 3.075 moles of N₂ will react with 18.4 moles of Li

We conver the moles to mass → 18.4 mol . 6.94g / 1mol = 128 g

4 0
3 years ago
A Questic
Ivanshal [37]

Answer:

No, it is not feasible because the Gibbs free energy change is positive

Explanation:

∆Hreaction= (-602 KJ/mol) - (-348 KJ/mol) = -254 KJ/mol

∆Sreaction = (42 + 27) J/Kmol - (33 + 44) J/K = -8J/Kmol

From;

∆G = ∆H - T∆S

∆G = 254 × 10^3 J/mol - [340K × (-8 J/Kmol)]

∆G = 2.57 × 10^5 J/mol

Note that when the change in free energy is positive, a reaction is non spontaneous. Only a reaction that has a negative change in free energy is spontaneous.

3 0
3 years ago
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