1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Shtirlitz [24]
2 years ago
12

A pitcher throws a baseball towards home plate. The baseball, which has a mass of 142 g, approaches the plate with 128 J of kine

tic energy.
Calculate the speed of the baseball.
Physics
1 answer:
mylen [45]2 years ago
5 0
Mass=142g
K.E=128 J
Speed or Velocity=?
K.E=1/2*m*v^2
128=1/2*142*v^2
128=72*v^2
v^2=128/72
v^2=1.777
by taking square rt 
v= 1.333ms-1
so the speed will be 1.333 ms-1
You might be interested in
Two separate but nearby coils are mounted along the same axis. A power supply controls the flow of current in the first coil, an
Anit [1.1K]

Answer:

b.only when the current in the first coil changes.

Explanation:

An induced current flow in the second coil only when there is a change in current in the first cool. A steady current will produce no change in flux (due to magnetic effect of a current) by the first coil, and according to Faraday, induced current is only produced when there is a change in flux linkage.

8 0
3 years ago
Que carro ese que está en la foto
Taya2010 [7]
Travis Scott!3&;8284$28&:!;&29395
7 0
2 years ago
Read 2 more answers
A projectile is fired horizontally from a height of 78.4 m at a speed of 300 m/sec. How far did it travel horizontally before hi
Mice21 [21]

Answer:

Explanation:

Using the formula for calculating range expressed as;

R = U√2H/g

U is the speed = 300m/s

H is the maximum height = 78.4m

g is the acceleration due to gravity = 9.8m/s²

Substitute into the fromula;

R = 300√2(78.4)/9.8

R = 300 √(16)

R = 300*4

R = 1200m

Hence the projectile travelled 1200m before hitting the ground

3 0
2 years ago
The MSDS for glacial acetic acid says that it is a flammable liquid that can severely burn any human tissue it comes in contact
Alex777 [14]

Answer: D) It should be handled in a fume hood, away from open flames.

3 0
2 years ago
an athlete whirls an 8.71 kg hammer tied to the end of a 1.5 m chain in a simple horizontal circle where you should ignore any v
-BARSIC- [3]

Answer:

T = 692.42 N

Explanation:

Given that,

Mass of hammer, m = 8.71 kg

Length of the chain to which an athlete whirls the hammer, r = 1.5 m

The angular sped of the hammer, \omega=1.16\ rev/s=7.28\ rad/s

We need to find the tension in the chain. The tension acting in the chain is balanced by the required centripetal force. It is given by the formula as follows :

F=m\omega^2r\\\\=8.71\times (7.28)^2\times 1.5\\\\=692.42\ N

So, the tension in the chain is 692.42 N.

5 0
2 years ago
Other questions:
  • Let this oscillator have the same energy as a mass on a spring, with the same k and m, released from rest at a displacement of 5
    14·1 answer
  • Does a brick have thermal energy? Also does paper haven't thermal energy?
    5·1 answer
  • Can some1 pls help me.
    9·1 answer
  • What is the potential energy of a 3 kg rock sitting at the top of a 21 meter high cliff?
    8·1 answer
  • A rocket is continuously firing its engines as it accelerates away from Earth. For the first kilometer of its ascent, the mass o
    5·1 answer
  • A naughty squirrel jumps from a tree limb onto a birdfeeder. The tree limb is 4.5 m above the ground and the top of the birdfeed
    7·1 answer
  • A boy is pedaling his bicycle at a velocity of 0.20km/ minute . How far will he travel in 2.5 hours
    8·2 answers
  • Calculate the nuclear binding energy per nucleon for 136^Ba if its nuclear mass is 135.905 amu.
    13·1 answer
  • Type in the correct values to correctly represent the valence electron configuration of oxygen: AsB2pC A = B = C = What is the c
    13·2 answers
  • The colour of the shadow of coloured objects is not same as the colour of the objects​
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!