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wlad13 [49]
3 years ago
13

What technologies are astronomers using to look for life on other planets? Why? help!!! please

Physics
1 answer:
Brilliant_brown [7]3 years ago
6 0
<h3><u>Technology used by astronomers to look for life on other plants:</u></h3>
  • Space-based Hubble and Spitzer telescopes and Green Bank telescopes are used.
  • Many new satellites are launched to trace earth like planets. Even the telescopes are carried by spacecrafts.
  • Astronomers are using Allen Telescope Array that comprises 42 radio antennas to get hold of signals over a wide range of radio frequencies that are tuned to listen to the regions nearer to the red dwarf star constellations.
  • Scientists needed telescopes that are capable of detecting planets like Earth in our planet’s neighborhood and see if any biological signatures connected to any microbial or other intelligent life can be found.
  • Radio signals are also being used to detect if the outside world has something to communicate so that they can be detected.
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Which statements about velocity are true?
OleMash [197]
<span>the speed of a direction</span>
5 0
3 years ago
Read 2 more answers
I'm not sure if the answer is A or B... someone help
Talja [164]
Its b i literally have had this exact question
8 0
3 years ago
A cheetah runs 5 miles in 60 seconds. How fast did the cheetah run in MILES per HOUR? Convert seconds into hours first, then sol
Vinil7 [7]

Answer:

300 miles per hour

Explanation:

Speed is distance per unit time, expressed as s=d/t where t is the time taken, d is distance covered and s is the speed.

Convering s to hrs

To convert seconds to hours, we knkw that 1 hour has 60 minutes and each minute has 60 seconds. Therefore, 1 hour has 60*60=3600 seconds

If 3600s=1 h

60 s=?

By cross multiplication 60s*1 h/3600s=1/60 hours

Given distance as 5 miles and time as 1/60 hours then the speed will be 5 divided by 1/60 hrs which is equivalent to 5*60=300 miles per hour

6 0
3 years ago
If you are at latitude 43 degrees north of Earth's equator, what is the angular distance (in degrees) from your zenith to the no
kirill115 [55]

Answer:

Your zenith is 43 N of 90 deg (equator)

Thus, your zenith is 90 - 43 = 47 deg

(At the N pole your zenith would be 0 deg from the N pole)

8 0
2 years ago
A speedboat is approaching a dock at 25 m/s (56 mph). When the dock is 150 m away, the driver begins to slow down. a) What accel
trasher [3.6K]

Answer:

a) -2.038 m/s²

b) 40.33 mph

c) 312.5 m

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration

v^2-u^2=2as\\\Rightarrow a=\frac{v^2-u^2}{2s}\\\Rightarrow a=\frac{0^2-25^2}{2\times 150}\\\Rightarrow a=-2.083\ m/s^2

Acceleration of the boat is -2.083 m/s² if the boat will stop at 150 m.

v^2-u^2=2as\\\Rightarrow v=\sqrt{2as+u^2}\\\Rightarrow v=\sqrt{2\times -1\times 150+25^2}\\\Rightarrow v=18.03\ m/s

Speed of the boat by when it will hit the dock is 18.03 m/s

Converting to mph

1\ mile=1609.34\ m

1\ h=3600\ seconds

18.03\times \frac{3600}{1609.34}=40.33\ mph

Speed of the boat by when it will hit the dock is 40.33 mph

v^2-u^2=2as\\\Rightarrow s=\frac{v^2-u^2}{2a}\\\Rightarrow s=\frac{0^2-25^2}{2\times -1}\\\Rightarrow s=312.5\ m

The distance at which the boat will have to start decelerating is 312.5 m

5 0
3 years ago
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