Answer:
A double-entry bookkeeping system is where a corresponding entry is made for every transaction.
Answer: hardness
Explanation:
Hardness is a measure of a material's ability to resist plastic deformation. In other words, it is a measure of how resistant material is to denting or scratching. Diamond, for example, is a very hard material. It is extremely difficult to dent or scratch a diamond. In contrast, it is very easy to scratch or dent most plastics.
Answer:
Amperes WB =<em> </em>![200J](https://tex.z-dn.net/?f=200J)
Explanation:
Amperes will flow back to the negative terminal because both the positive terminal and negative terminal contain the equivalent amount of current that will flow and it works in the starter motor.
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Answer:
The pressure difference across hatch of the submarine is 3217.68 kpa.
Explanation:
Gauge pressure is the pressure above the atmospheric pressure. If we consider gauge pressure for finding pressure differential then no need to consider atmospheric pressure as they will cancel out. According to hydrostatic law, pressure varies in the z direction only.
Given:
Height of the hatch is 320 m
Surface gravity of the sea water is 1.025.
Density of water 1000 kg/m³.
Calculation:
Step1
Density of sea water is calculated as follows:
![S.G=\frac{\rho_{sw}}{\rho_{w}}](https://tex.z-dn.net/?f=S.G%3D%5Cfrac%7B%5Crho_%7Bsw%7D%7D%7B%5Crho_%7Bw%7D%7D)
Here, density of sea water is
, surface gravity is S.G and density of water is
.
Substitute all the values in the above equation as follows:
![S.G=\frac{\rho_{sw}}{\rho_{w}}](https://tex.z-dn.net/?f=S.G%3D%5Cfrac%7B%5Crho_%7Bsw%7D%7D%7B%5Crho_%7Bw%7D%7D)
![1.025=\frac{\rho_{sw}}{1000}](https://tex.z-dn.net/?f=1.025%3D%5Cfrac%7B%5Crho_%7Bsw%7D%7D%7B1000%7D)
kg/m³.
Step2
Difference in pressure is calculated as follows:
![\bigtriangleup p=rho_{sw}gh](https://tex.z-dn.net/?f=%5Cbigtriangleup%20p%3Drho_%7Bsw%7Dgh)
![\bigtriangleup p=1025\times9.81\times320](https://tex.z-dn.net/?f=%5Cbigtriangleup%20p%3D1025%5Ctimes9.81%5Ctimes320)
pa.
Or
![\bigtriangleup p=(3217680pa)(\frac{1kpa}{100pa})](https://tex.z-dn.net/?f=%5Cbigtriangleup%20p%3D%283217680pa%29%28%5Cfrac%7B1kpa%7D%7B100pa%7D%29)
kpa.
Thus, the pressure difference across hatch of the submarine is 3217.68 kpa.