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4 years ago

Near the surface of the earth the acceleration do to gravity is equal to......?

1 answer:

5 0

That's 9.8 meters/second² .

Anything that falls to the ground, no matter whether it's a feather
or a battleship, falls with that same acceleration. At least it would
if there were no air in the way.

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When dolphin swims close to its prey, it transmits sound waves to figure out details (like direction where the fish is moving) o

svet-max [94.6K]

Answer:

The frequency of the waves depends on the distance between wave fronts - considering a front as a maximum disturbance of the wave

(Consider the waves emitted by an organ pipe: condensation and rarefactions)

The waves themselves are a fixed distance apart -

as one moves towards the source the waves received will be closer together (higher frequency)

So if the frequency received increases, the distance between the source and the observer must be decreasing

8 0

3 years ago

At a pressure of one atmosphere methane boils at −161°C and freezes at −182.5°C. Consider a temperature scale where the boiling

lawyer [7]

Answer:

$-421.627906977\^{\circ}M$

Explanation:

Absolute zero in the Kelvin scale = -273.15 °C

Temperature difference in the boiling and freezing point

$-161-(-182.5)=21.5\ ^{\circ}C$

Change in 21.5°C = Change of 100°C in M

$1^{\circ}C=\dfrac{100}{21.5}=4.6511627907\ ^{\circ}M$

Difference in the Celsius scale

$-182.5-(-273.15)=90.65\ ^{\circ}C$

Change in $90.65\ ^{\circ}C$ corresponds to

$4.6511627907\times 90.65=421.627906977\ ^{\circ}M$

Therefore the absolute zero in the Methane scale is

$-421.627906977\ ^{\circ}M$

3 0

3 years ago

An 6 kg object accelerating from 17 m/s to 10 m/s. What is the change in momentum of the object?

Oksana_A [137]

Answer:

the change is = 17 × 10 = 170 =28.33

3 0

3 years ago

Maya uses a tuning fork of frequency 250 Hz to produce transverese waves on a stretched string. Her friend justin measure the di

Goshia [24]

Answer:

The velocity of the wave is 12.5 m/s

Explanation:

The given parameters are;

he frequency of the tuning fork, f = 250 Hz

The distance between successive crests of the wave formed, λ = 5 cm = 0.05 m

The velocity of a wave, v = f × λ

Where;

f = The frequency of the wave

λ = The wavelength of the wave - The distance between crests =

Substituting the known values gives;

v = 250 Hz × 0.05 m = 12.5 m/s

The velocity of the wave, v = 12.5 m/s.

6 0

3 years ago

The pressure exerted by a liquid column of depth 0.5 m on the base of its

Alik [6]

Answer:

1020.4kg/m³

35m³

Explanation:

Given parameters:

Depth = 0.5m

Pressure exerted = 5000N/m²

Unknown = density of the liquid = ?

Solution:

To find the density of this unknown liquid, we use the expression below:

Pressure of liquid = density x height x acceleration due to gravity

5000 = density x 0.5 x 9.8

Density = 1020.4kg/m³

Density of water = 1000kg/m³

Mass of water = 35000kg

Unknown:

Volume of water = ?

Solution:

The volume of water can be derived from the expression below:

Volume = $\frac{mass}{density}$

Volume = $\frac{35000}{1000}$ = 35m³

4 0

3 years ago