Answer:height above ground at which projectile have velocity
0.5v is (0.0375v^2)
Explanation:
Using Vf = Vi - gt
Where Vf is final velocity
Vi is initial velocity
g is the acceleration due to gravity
t is the time taken
So, 0.5v = v - gt
t = 0.05v
Therefore height h = vt - 0.5gt^2
Subtitute t
h = 0.05v^2 - 0.0125v^2
h = 0.0375v^2
Answer:
Explanation:
Given that,
Initially, the spaceship was at rest, u = 0
Final velocity of the spaceship, v = 11 m/s
Distance accelerated by the spaceship, d = 213 m
We need to find the acceleration experienced by the occupants of the spaceship during the launch. It is a concept based on the equation of kinematics. Using the third equation of motion to find acceleration.
So, the acceleration experienced by the occupants of the spaceship is 
.
Answer:
A.
Explanation:
A man using a microwave to boil water
The first box is Acceleration
the second box is Speed
the third box is Speed
the fourth box is velocity
the fifth box is Speed.
The reason the first box is acceleration is because let's say you are about to go up a hill you need to add acceleration to make it up the hill, I was going to say speed but it wouldn't said what mph was.
The reason the second, third,and fifth box is speed is because it is telling up that an object is going _mph (the blank is where you put your estimate of speed of an object).
The reason the fourth box is velocity is because velocity is both magnitude and direction so in the fourth box it says that the race car made a slight left turn which is a direction that the car is going in.
Hope this helped :)
Have a great day
