Answer:
.7917 m/s
Explanation:
This is a conservation of momentum question. You have an object initially at rest (cart) so that object is initially at 0 momentum. Indiana Jones is 83.5 kg and running 3.75 m/s so he starts with a momentum of 313.125 kg * m/s because momentum is equal to mass * velocity. Once the person jumps in the cart, the cart and the person can be considered one object and by conservation of momentum, the momentum of the Indiana-cart system is equal to 313.125 kg * m/s. By that, we can set that momentum equal to the combined mass * joint velocity. So 313.125 = (83.5kg + 312kg) * joint velocity. Then just solve for the velocity. The answer should be smaller than the intial velocity of the person of 3.75 m/s because the mine cart is HUGE at 312kg.
Here’s a good photo to reference when converting in the metric system.
Each time you move down a step you move the decimal to the right, each time you move up a step you move the decimal to the left.
We are going from 1.2 kg or kilograms, which is at the very top left of the ladder. To get to mg or milligrams, we would have to make six jumps, so we’d move the decimal over six times.
1.2 > 12. > 120. > 1200. > 12000. > 120000. > 1200000.
So our final answer would be 1,200,000mg.
Answer:
evaporation
Explanation:
without 4he evaporation it can even start the cycsl
Answer:
The terminal speed of his is 137.68 m/s.
Explanation:
Given that,
Mass of skydiver = 78 kg
Area of box
Drag coefficient = 0.80
Density of air 
We need to calculate the terminal velocity
Using formula of drag force
Where,
= density of air
A = area
C= coefficient of drag
Put the value into the formula
Hence, The terminal speed of his is 137.68 m/s.
Reproduction ,if I’m not mistaking if I get u the wrong answer just report my comment
