Answer:
grams of lithium bromide produced = 36.2642309286 ≈ 36.30 g
Explanation:
The equation of the reaction is as follows ;
Lithium hydroxide + hydrogen bromide → Lithium Bromide + water
LiOH + HBr → LiBr + H2O
The equation is already balanced
Molecular mass of LiOH = 6.941 + 15.999 + 1.00784
Molecular mass of LiOH = 23.94784 g
Molecular mass of LiBr = 6.941 + 79.904 = 86.845 g
From the equation
LiOH + HBr → LiBr + H2O
23.94784 g of lithium hydroxide produces 86.845 g of lithium bromide
10 g of lithium hydroxide will produce ?
cross multiply
grams of lithium bromide produced = 10 × 86.845/23.94784
grams of lithium bromide produced = 868.45/23.94784
grams of lithium bromide produced = 36.2642309286 ≈ 36.30 g
