The formula for finding Density is Mass over Volume.
Explanation:
So 35g over 25ml
Answer:
clastic, organic, and chemical
Explanation:
As we know that density is the amount of mass present in a liter of solution.
Mathematically, density = ![\frac{mass}{volume}](https://tex.z-dn.net/?f=%5Cfrac%7Bmass%7D%7Bvolume%7D)
As it is given that density of water is 1 g/ml and volume is 175 mL. So, mass of water will be calculated as follows.
density = ![\frac{mass}{volume}](https://tex.z-dn.net/?f=%5Cfrac%7Bmass%7D%7Bvolume%7D)
1 g/ml = ![\frac{mass}{175 ml}](https://tex.z-dn.net/?f=%5Cfrac%7Bmass%7D%7B175%20ml%7D)
mass = 175 g
It is known that 18 g of water contains 1 mole of water. Hence, number of moles present in 175 g of water will be calculated as follows.
No. of moles = ![\frac{mass}{\text{molar mass}}](https://tex.z-dn.net/?f=%5Cfrac%7Bmass%7D%7B%5Ctext%7Bmolar%20mass%7D%7D)
= ![\frac{175 g}{18 g/mol}](https://tex.z-dn.net/?f=%5Cfrac%7B175%20g%7D%7B18%20g%2Fmol%7D)
= 9.72 mol
This means that we have 9.72 moles of ethanol also.
Hence, volume of ethanol present in 175 ml of water will be as follows.
No. of moles of ethanol = ![\frac{density \times Volume}{\text{molar mass of ethanol}}](https://tex.z-dn.net/?f=%5Cfrac%7Bdensity%20%5Ctimes%20Volume%7D%7B%5Ctext%7Bmolar%20mass%20of%20ethanol%7D%7D)
9.72 mol = ![\frac{0.789 g/ml \times Volume}{46 g/mol}](https://tex.z-dn.net/?f=%5Cfrac%7B0.789%20g%2Fml%20%5Ctimes%20Volume%7D%7B46%20g%2Fmol%7D)
Volume = 566.69 ml
Thus, we can conclude that 566.69 ml volume of ethanol contains the same number of molecules as are present in 175 ml of
.
Answer:
<h2>both of them</h2>
Explanation:
<h3>I hope it's helpful for you ✌</h3>
Answer:
1.58L
Explanation:
Given parameters:
Initial volume = 1.2L
Initial temperature = 28.5°C = 28.5 + 273 = 301.5K
Final temperature = 125°C = 125 + 273 = 398K
Unknown:
New volume = ?
Solution:
Volume and temperature relationship is resolved using the Charles's law.
The law states that "the volume of a fixed mass of a gas varies directly as its absolute temperature if the the pressure is constant".
So;
=
V1 is the initial volume
T1 is the initial temperature
V2 is the new volume
T2 is the new temperature
=
301.5V2 = 477.6
V2 = 1.58L