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2 years ago

Which statement is valid.

Physics

1 answer:

Serhud [2]2 years ago

3 0

Answer:

as an object gains speed it gains kinetic energy

Explanation:

i am mixed with the very first one i dont really know if its right so if its wrong my bad

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Find the period of the leg of a man who is 1.83 m in height with a mass of 67 kg. The moment of inertia of a cylinder rotating a

Lady bird [3.3K]

Answer:

1.54 s

Explanation:

Considering that the legs constitute 16% of the total weight of the man then mass, $m= \frac {16}{100}\times 67=10.72 Kg$

The legs also constitute 48% of his height hence $H=\frac {48}{100}\times 1.83=0.8784 m$

The moment of inertia of a cylinder rotating about a perpendicular axis at one end is $\frac {ml^{2}}{3}$ hence $I=\frac {10.72\times 0.8784^{2}}{3}=2.757135974Kg.m^{2}$

We also know that the period is given by $2\pi \sqrt{\frac {I}{mgh}}$

Here, h=0.5H= 0.5*0.8784=0.4392 m

Taking g as 9.81 kg/m2 then

$T= 2\pi \sqrt{\frac {2.757135974}{10.72\times 9.81\times 0.4392}}\\=1.535132615 s\\\boxed{\approx 1.54 s}$

3 0

3 years ago

A gas has a pressure of 48atm in a 15.5L container. It was found that at 25∘C the gas occupied a volume of 25L and had a pressur

EleoNora [17]

Answer:

130.165636364°C

Explanation:

P = Pressure

V = Volume

n = Number of moles

R = Gas constant = 0.082 L atm/mol K

From ideal gas law we have

$PV=nRT\\\Rightarrow n=\dfrac{PV}{RT}\\\Rightarrow n=\dfrac{22\times 25}{0.082\times (25+273.15)}\\\Rightarrow n=22.496451696\ moles$

$PV=nRT\\\Rightarrow T=\dfrac{PV}{nR}\\\Rightarrow T=\dfrac{48\times 15.5}{22.496451696\times 0.082}\\\Rightarrow T=403.315636364\ K$

The initial temperature is $403.315636364-273.15=130.165636364\ ^{\circ}C$

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3 years ago

A voltage source provides ___________ required for electric current.

Gnoma [55]

Two terminal device which can maintain a fixed voltage. Hope this help I need more detail in your question this is all I can provide. :)

8 0

2 years ago

What does the Nucleolus do?

SCORPION-xisa [38]

Answer:

Explanation:

6 0

3 years ago

Read 2 more answers

An electric wall clock has a second hand 15 cm long. at the tip of his hand, what is the magnitude of the velocity?

Mila [183]

The velocity of the tip of the second hand is 0.0158 m/s

Explanation:

First of all, we need to calculate the angular velocity of the second hand.

We know that the second hand completes one full circle in

T = 60 seconds

Therefore, its angular velocity is:

$\omega = \frac{2\pi}{T}=\frac{2\pi}{(60)}=0.105 rad/s$

Now we can calculate the velocity of a point on the tip of the hand by using the formula

$v=\omega r$

where

$\omega=0.105 rad/s$ is the angular velocity

r = 15 cm = 0.15 m is the radius of the circle (the distance of the point from the centre of rotation)

Substituting,

$v=(0.105)(0.15)=0.0158 m/s$

Learn more about angular motion here:

brainly.com/question/9575487

brainly.com/question/9329700

brainly.com/question/2506028

#LearnwithBrainly

7 0

2 years ago