Answer:
It is given that power = 5000 W for 120 V and resistance is
per 1000 ft of wire. The wire is 750 ft away from 120 V source. We need find the voltage delivered to this load.
![Power, P=Voltage(E)\times Current(I)](https://tex.z-dn.net/?f=Power%2C%20P%3DVoltage%28E%29%5Ctimes%20Current%28I%29)
![\Rightarrow I=\frac{P}{E}=\frac{5000W}{120V}=41.67 A](https://tex.z-dn.net/?f=%5CRightarrow%20I%3D%5Cfrac%7BP%7D%7BE%7D%3D%5Cfrac%7B5000W%7D%7B120V%7D%3D41.67%20A)
Resistance of 750 ft wire, =![R=\frac{1.24\Omega}{1000 ft}\times750 ft=0.93\Omega](https://tex.z-dn.net/?f=R%3D%5Cfrac%7B1.24%5COmega%7D%7B1000%20ft%7D%5Ctimes750%20ft%3D0.93%5COmega)
Using Ohm's Law:
Voltage delivered to the load, ![V=IR](https://tex.z-dn.net/?f=V%3DIR)
![\Rightarrow V=41.67A\times0.93\Omega=38.75 V](https://tex.z-dn.net/?f=%5CRightarrow%20V%3D41.67A%5Ctimes0.93%5COmega%3D38.75%20V)
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