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3 years ago

To protect a material from the influence of an external magnetic field, the material should be kept in?

1 answer:

5 0

To protect a material from the influence of an external magnetic field, the material should be kept in soft iron ring.

So the correct answer is A.

Hope this helps,

Davinia.

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A transverse wave is set up in a very long string. The oscillator is set at 20.0 Hz, and the wave speed is 78 m/s. The amplitude

Sedbober [7]

To solve this problem we must apply the concepts related to Tangential Acceleration based on angular velocity and acceleration, and therefore, we must also calculate angular velocity based on the given frequency. For all these problems we will take the Units to the International System. The maximum acceleration would then be defined as,

$a_{max} = \omega^2 A$

Here,

$\omega$ = Angular velocity

A = Amplitude

At the same time the angular velocity is described as,

$\omega = 2\pi f$

Here f means the frequency of the wave. Substituting,

$\omega = 2 \pi (20)$

$\omega = 40\pi$

$A = 5.2cm$

$A = 0.052m$

Replacing at the first equation,

$a_{max} = (40\pi )^2 (0.052)$

$a_{max} = 821.15m/s^2$

Therefore the maximum particle acceleration for a point on the string is $821.15m/s^2$

6 0

4 years ago

A 4n force is applied to an object with a mass of 2kg what is the accelertion of the object

Pavel [41]

As per Newton's law we know that

F = ma

here we know that

F = 4 N

m = 2 kg

so from this equation we will have

4 = 2 a

a = 4/2 = 2 m/s^2

so the acceleration will be 2 m/s^2

5 0

3 years ago

When you sweat, what is the external stimuli? I need help asap.

mixer [17]

Answer:

An External Stimulus is a stimulus that comes from outside an organism. Examples: You feel cold so you put on a jacket. When you sweat, the external stimulus is either you're anxious or hot.

Explanation:

hope it helps! <3

8 0

3 years ago

How high can a body vertically thrown with a speed of 40m/s raise after 3 sec (neglecting air

Tcecarenko [31]

y = 75.9 m

Explanation:

y = -(1/2)gt^2 + v0yt + y0

If we put the origin of our coordinate system at the point where a body is launched, then y0 = 0.

y = -(1/2)(9.8 m/s^2)(3 s)^2 + (40 m/s)(3 s)

= -44.1 m + 120 m

= 75.9

5 0

3 years ago

How does the end point differ from the equivalence point of a titration?

Gwar [14]

Answer:

Equivalence point and end point are terminologies in pH titrations and they are not the same. 

Explanation:

In a titration the substance added slowly to a solution usually through a pippette is called titrante and the solution to which it is added is called titrand. In acid-base titrations acid is added to base or base is added to acid.the strengths of the acid and base titrated determines the nature of the final solution.

At equivalence point the number of moles of the acid will be equal to the number of moles of the base as given in the equation. The nature of the final solution determines the pH at equivalence point. 

A pH less than 7 will be the result if the resultant is acidic and if it is basic the pH will be greater than 7. In a strong base-strong acid and weak base-weak acid titration the pH at the equivalence point will be 7 indicating neutral nature of the solution. 

3 0

3 years ago