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jek_recluse [69]
3 years ago
15

Su prepares a presentation about the industrial revolution. She wants to change the font on the second slide of her presentation

. How can she accomplish this task? Check all that apply
Engineering
1 answer:
choli [55]3 years ago
8 0

Font of the slide can be edited in the presentations :-

Explanation

By following these steps Su can change the presentation font of her second slide.

1. Edit- As Su open her second slide , there will be a option of "Edit" on the top right corner of the screen.

2. Font- As the various options are available on the screen such as  font size , add image etc ,click on the option "Font"

3. Drop Down- As you click on font option , it will be followed by a drop down option with various type of fonts. Su can select the font she wishes to add in her presentation and look it more precise by adjusting the Font Size.

4 Save- Save the changes made in the slide for future.        

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Lithium at 20°C is BCC and has a lattice constant of 0.35092 nm. Calculate a value for the atomic radius of a lithium atom in na
Nutka1998 [239]

Answer:

the atomic radius of a lithium atom is 0.152 nm

Explanation:

Given data in question

structure = BCC

lattice constant  (a) = 0.35092 nm

to find out

atomic radius of a lithium atom

solution

we know structure is BCC

for BCC radius formula is \sqrt{3} /4 × a

here we have known a value so we put a in radius formula

radius =  \sqrt{3} /4 × a

radius =  \sqrt{3} /4 × 0.35092

radius = 0.152 nm

so the atomic radius of a lithium atom is 0.152 nm

5 0
3 years ago
A fluidis flowing through a capillary
Illusion [34]

Answer:

The velocity of the fluid is 1.1012 m/s

Solution:

As per the question, for the fluid:

Diameter of the capillary tube, d = 1.0 mm = 1.0\times 10^{- 3} m

Reynolds No., R  = 1000

Kinematic viscosity,  \mu_{k} = 1.1012\times 10^{- 6} m^{2}/s

Now, for the fluid velocity, we use the relation:

R = \frac{v_{f}\times d}{\mu_{k}}

where

v_{f} = velocity of fluid

v_{f} = \frac{R\times \mu_{k}}{d}

v_{f} = \frac{1000\times 1.1012\times 10^{- 6}}{1.0\times 10^{- 3}} = 1.1012 m/s

6 0
3 years ago
Before you calculate the moment capacity for a steel beam, you have to determine the classification of beam.
kirill [66]

Answer:

True

Explanation:

True - because different classification of steel beam have different yield strength.

The moment capacity for a steel beam is given by;

M = Mn / Ωₙ

where;

M - the maximum moment acting on the beam

Ωₙ - is the Safety Factor for Elements in Bending = 1.67

Mn - nominal moment of the steel, given as

M_n = Z_x *f_y

where;

Zₓ - the Plastic Section Modulus in the x or strong axis.

f_y - is the Yield Strength of the Steel (A36W, A46 W or A50W)

A36W = 36 ksi

A46 W = 46 ksi

A50W = 50 ksi

Thus, before you calculate the moment capacity for a steel beam, you have to determine the classification of beam, for the yield strength of the steel beam.

6 0
4 years ago
Technician A says that the mainline pressure is usually higher in manual first gear than it is when the gear selector is in the
Black_prince [1.1K]

Answer:

Technician A & B

Explanation:

3 0
4 years ago
Read 2 more answers
What is a calibration? What are the four types of instrument errors?
Nastasia [14]

Answer and Explanation:

Calibration can be defined as a process where the accuracy of an instrument is measured and are compared with the known and set standards for calibration.

The instrument errors can be defined any deflection from the true value in the measurement or we can say that any difference between measured value and actual or true value results in instrument errors.

The instrument errors are further classified into 4 types:

a). Random errors :

These error arise as the result of random, unpredictable or irregular changes in an experimental set up.

b). Systematic errors :

These errors arises as a result of fault in the instrument or as a result of the effects of some external factors.

c). Gross errors:

These errors are a result of human errors in measurement while recording the reading, etc

d). Zero errors:

This error arises when the reading of the instrument is false while the measured value is equal to zero.

This is when the needle of an ammeter or voltmeter is not at zero but somewhere above or below it when the supply is not given.

7 0
4 years ago
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