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Whitepunk [10]
3 years ago
5

Consider equal volumes (say 1 l of a given substance in the solid, liquid, and gas phases. arrange them in order of decreasing m

ass based on the trend for the average substance. if the mass difference between samples is relatively small (10% or less, rank the items as equivalent.
Physics
2 answers:
lana [24]3 years ago
6 0
The particles in solids are closely packed together, which means that the amount of substance in solids are more compared to the liquid and gases of having the same volume. The arrangement of the phases in decreasing masses will then be,
                                      solid, liquid, and gas
Ad libitum [116K]3 years ago
4 0

Answer:

In the common cases, solids have all the particles close together and held in place, liquids have the particles close together (less than solids) but not held, and gases have the particles more separated than the previous cases.

So, in a defined volume, usually, solids will have more mass, this is because particles are close together and you can put more particles in a given volume, then comes liquid, and the comes to gas.

An exception of this can be water, where the solid-state is less dense than the liquid state (this is why ice floats in liquid water)

Here for a fixed volume, liquid water has more mass than the solid-state, and the solid-state has more mass than the gas state.

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A box of mass 60 kg is at rest on a horizontal floor that has a static coefficient of friction of 0.6 and a kinetic coefficient
gavmur [86]

Answer:

a) The minimum force required to start moving the box is 352.86 N

b) i) The friction force for the box in motion is 147.025 N

ii) The acceleration of box is 4.21625 m/s²

Explanation:

The parameters of the box at rest and the floor are;

The mass of the box = 60 kg

The static coefficient friction of the floor = 0.6

The kinetic coefficient friction of the floor = 0.25

Frictional force = Normal force × Friction coefficient

For an horizontal floor and the box laying on the floor, we have;

The normal force = The weight of the box = Mass of the box × Acceleration due to gravity, g

The acceleration due to gravity, g = 9.81 m/s²

The weight of the box  = 60 × 9.81 = 588.6 N

a) The static coefficient gives the frictional force observed by the box and which must be surpassed to bring about motion

Therefore;

The minimum force required to start moving the box = The static frictional force = Weight of the box × The static coefficient of friction

The minimum force required to start moving the box = 588.1 × 0.6 = 352.86 N

The minimum force required to start moving the box = 352.86 N

b) i) When an horizontal force of 400 N is applied, the applied force is larger than the static friction force, and the box will be in motion with the kinetic coefficient of friction being the source of friction

The friction force for the box in motion = 588.1 × 0.25 = 147.025 N

ii) The force, F with the box is in motion, is given as follows;

F = Mass of box × Acceleration of box, a = Applied force - Kinematic friction force

F = 60 × a = 400 - 147.025 = 252.975 N

60 × a = 252.975 N

a = 252.975 N/(60 kg) = 4.21625 m/s²

Acceleration of box, a = 4.21625 m/s².

6 0
2 years ago
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