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morpeh [17]
3 years ago
10

How can "Ali" distinguish the interference patterns produced by diffraction gratings from the interference patterns produced by

a double-slit?
The interference pattern from a diffraction grating will have a wide, central bright band with alternate dark and bright bands on both sides, and the interference pattern will have an equally spaced dark and bright band.
The interference pattern from a diffraction grating will have a wide, central dark band with bright and dark bands on both sides, and the interference pattern will have bright narrow lines between dark bands.
The interference pattern from a diffraction grating will have narrow, equally spaced bright lines, and the interference pattern will have bright and dark bands.
The interference pattern from a diffraction grating will have narrow, equally spaced bright lines, and the interference pattern will have a wide central bright band with dark and bright bands on either side.
Physics
1 answer:
I am Lyosha [343]3 years ago
3 0

Answer:

The interference pattern from a diffraction grating will have a wide, central bright band with alternate dark and bright bands on both sides, and the interference pattern will have an equally spaced dark and bright band.

Explanation:

In diffraction pattern we know that the distance between two consecutive minimum position is maximum

So here position of minimum is given as

asin\theta = N\lambda

now we have central maximum is of maximum width while all other have width of decreasing order.

While when we use Young's double slit pattern then we can say that position of all maximum and minimum intensity on the screen will be at same distance.

so here we have

y = \frac{N\lambda L}{d}

so all the maximum and minimum intensity will have equal width.

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Wall-E the robot is resting when he randomly explodes into two pieces that fly off in opposite directions. His head has a mass o
Brut [27]

Answer:

<em>The body flies off to the left at 9.1 m/s</em>

Explanation:

<u>Law Of Conservation Of Linear Momentum </u>

It states the total momentum of a system of bodies is conserved unless an external force is applied to it. The formula for the momentum of a body with mass m and speed v is  

P=mv.  

If we have a system of bodies, then the total momentum is the sum of the individual momentums:

P=m_1v_1+m_2v_2+...+m_nv_n

If a collision occurs and the velocities change to v', the final momentum is:

P'=m_1v'_1+m_2v'_2+...+m_nv'_n

Since the total momentum is conserved, then:

P = P'

In a system of two masses, the equation simplifies to:

m_1v_1+m_2v_2=m_1v'_1+m_2v'_2\qquad\qquad[1]

Wall-E robot is initially at rest, its two parts together. His head has a mass of m1=0.75 kg and his body has a mass of m2=6.2 kg. Both parts have initial speeds of zero v1=v2=0.

After the explosion, his head flies off to the right at v1'=75 m/s. We are required to find the speed of his body v2'. Solving [1] for v2':

\displaystyle v'_2=\frac{m_1v_1+m_2v_2-m_1v'_1}{m_2}

Substituting values:

\displaystyle v'_2=\frac{0.75*0+6.2*0-0.75*75}{6.2}

\displaystyle v'_2=-9.1 \ m/s

The body flies off to the left at 9.1 m/s

3 0
3 years ago
Which is not a principle of fitness?<br> Overload<br> Height<br> Specificity<br> Individuality
Nitella [24]

Answer:

Height

Explanation:

7 0
3 years ago
Read 2 more answers
A satellite is in a circular Earth orbit of radius r. The area A enclosed by the orbit depends on r2 because A = πr2. Determine
Salsk061 [2.6K]

Answer:

a. T=r^{3/2}

b. K=\frac{1}{r}

c. v=\frac{1}{\sqrt{r}}

d. v=\sqrt{r}

Explanation:

To make analysis about the satellite circular earth the depends or r and A

T^2=\frac{4\pi}{GM}*r^3

K=\frac{GM*m}{2*r}

a.

T^2=r^3

T=r^{3/2}

b.

K=\frac{GM*m}{2}*\frac{1}{r}

K=\frac{1}{r}

c.

K=\frac{1}{2}*m*v^2

v^2=\frac{2*K}{m}=\frac{2*Gm*m}{2*m*r}

v=\frac{1}{\sqrt{r}}

d.

v=\sqrt{2*GMr}

v=\sqrt{r}

3 0
3 years ago
If a cheetah can maintain a constant speed of 25 m/s, it will cover 25 meters every second. At this rate, how far will it travel
Ksju [112]
10 seconds 25m*10s= 250m
60 seconds 25m*60s=1500m
5 0
4 years ago
Which one has larger kinetic energy: a 500-kg object moving at 40 m/s or a 1000-kg object moving at 20 m/s?
erma4kov [3.2K]
Kinetic  energy is energy possess by an object due to it motion.

Mass 1;  m = 500 Kg   Velocity 1;  V = 40 m/s

Mass 2;  m = 1000 Kg   Velocity 2;  V = 20 m/s

Formula: K.E = 1/2mv²

For Mass 1  K.E = 1/2(500 Kg)(40 m/s)² = 400, 000 J

For Mass 2  K.E = 1/2(1000 Kg)(20 m/s)² = 200,000 J

This solution shows that a larger velocity will have a greater kinetic energy.


7 0
4 years ago
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