1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
morpeh [17]
3 years ago
10

How can "Ali" distinguish the interference patterns produced by diffraction gratings from the interference patterns produced by

a double-slit?
The interference pattern from a diffraction grating will have a wide, central bright band with alternate dark and bright bands on both sides, and the interference pattern will have an equally spaced dark and bright band.
The interference pattern from a diffraction grating will have a wide, central dark band with bright and dark bands on both sides, and the interference pattern will have bright narrow lines between dark bands.
The interference pattern from a diffraction grating will have narrow, equally spaced bright lines, and the interference pattern will have bright and dark bands.
The interference pattern from a diffraction grating will have narrow, equally spaced bright lines, and the interference pattern will have a wide central bright band with dark and bright bands on either side.
Physics
1 answer:
I am Lyosha [343]3 years ago
3 0

Answer:

The interference pattern from a diffraction grating will have a wide, central bright band with alternate dark and bright bands on both sides, and the interference pattern will have an equally spaced dark and bright band.

Explanation:

In diffraction pattern we know that the distance between two consecutive minimum position is maximum

So here position of minimum is given as

asin\theta = N\lambda

now we have central maximum is of maximum width while all other have width of decreasing order.

While when we use Young's double slit pattern then we can say that position of all maximum and minimum intensity on the screen will be at same distance.

so here we have

y = \frac{N\lambda L}{d}

so all the maximum and minimum intensity will have equal width.

You might be interested in
Bank A has a leverage ratio of 10, while Bank B has a leverage ratio of 20. Similar losses on bank loans at the two banks cause
tamaranim1 [39]

Answer:

<u><em>note:</em></u>

<u><em>find the attached solution:</em></u>

3 0
3 years ago
Which of the following statements CANNOT be supported by Kepler's laws of planetary motion?
horsena [70]

Answer:

B) A planet's speed as it moves around the sun will not be the same in six months.

Explanation:

A planet's speed as it moves around the sun will not be the same in six months, is a  statement that CANNOT be supported by Kepler's laws of planetary motion.

8 0
3 years ago
Read 2 more answers
Unlike the majority of psychologists, psychiatrists __________. A. can diagnose disorders B. use psychotherapy C. treat people w
ludmilkaskok [199]
D prescribe medication

3 0
3 years ago
Read 2 more answers
Help Please
densk [106]

Answer:

Energy=3.1times 10^-17 J

Rest mass: 6.2 kg

Speed: 47.5 m/s

Wavelength: 2.659 times 10^-6

Momentum: 67.3 kg(m/s)

Explanation:

3 0
3 years ago
A fuel pump sends gasoline from a car's fuel tank to the engine at a rate of 5.64 10-2 kg/s. the density of the gasoline is 735
Irina18 [472]
Given:
Gasoline pumping rate, R = 5.64 x 10⁻² kg/s
Density of gasoline, D = 735 kg/m³
Radius of fuel line, r = 3.43 x 10⁻³ m

Calculate the cross sectional area of the fuel line.
A = πr² = π(3.43 x 10⁻³ m)² = 3.6961 x 10⁻⁵ m²

Let v =  speed of pumping the gasoline, m/s
Then the mass flow rate is 
M = AvD = (3.6961 x 10⁻⁵ m²)*(v m/s)*(735 kg/m³) = 0.027166v kg/s

The gasoline pumping rate is given as 5.64 x 10⁻² kg/s, therefore
0.027166v = 0.0564
v = 2.076 m/s

Answer:  2.076 m/s
The gasoline moves through the fuel line at 2.076 m/s.
7 0
3 years ago
Read 2 more answers
Other questions:
  • Will mark as brainliest if correct!!!!!!!!!!!!!!!!!!!!!!!!!
    9·2 answers
  • A rigid layer that lies outside the cell’s membrane is
    12·1 answer
  • A satellite is orbiting Earth in an approximately circular path. It completes one revolution each day (86,400 seconds). Its orbi
    11·1 answer
  • When starting a foot race, a 70.0-kg sprinter exerts an average force of 650 n backward on the ground for 0.800 s. what is his f
    13·1 answer
  • Give an example of a situation when it would be appropriate to round a number and a situation in which it would not be appropria
    12·1 answer
  • A 90.0-kg fullback running east with a speed of 5.00 m/s is tackled by a 95.0-kg opponent running north with a speed of 3.00 m/s
    14·1 answer
  • Has anyone read the book Third level
    9·2 answers
  • Geosynchronous satellites orbit the Earth at a distance of 42 000 km from the Earth's center. Their angular speed at this height
    13·1 answer
  • A good alternative to sit ups is<br><br> A. Crunches<br><br> B. Leg Raises<br><br> C. Side Twists
    9·1 answer
  • Antonio has been told that he needs to work on his self- awareness. What might he do to most improve this skill
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!