Answer:
Explanation:
Nuclear fusion of a form of nuclear reaction in which two small atomic nuclei combines to form larger ones with the release of a large amount of energy.
For example;
²₁H + ²₁H → ⁴₂He + Energy
The energy released in a nuclear reaction provides the needed temperature for another set of ²H atoms to fuse. This process in turn yields another ⁴He with the release of a lot of energy. Thus, enormous release of energy accompanies a nuclear reaction.
It is based on this principle that an hydrogen bomb is formed.
Answer:
4.00 mol
Explanation:
= 3.994585118 mol
(If you round Be mass to 9 you get 4 mol)
Answer:

Explanation:
Hello,
In this case, the first step is to compute the molarity of the first solution, for which we consider the molar mass of iron (III) nitrate that is 241.86 g/mol to compute the moles in 100.00 mL (0.1 L) of solution:

Which is actually the concentration of iron (III) ions. Therefore, for 10.00 mL of such solution, the concentration until a dilution to 250.0 mL results being:

Best regards.
Answer:
1)
is the average rate of formation of bromine gas during the same time interval.
2)
is the average rate of consumption of
during the same time interval.
Explanation:

1 ) Rate of the reaction : R
![R=-\frac{1}{5}\frac{d[Br^-]}{dt}=\frac{1}{2}\frac{d[Br_2]}{dt}](https://tex.z-dn.net/?f=R%3D-%5Cfrac%7B1%7D%7B5%7D%5Cfrac%7Bd%5BBr%5E-%5D%7D%7Bdt%7D%3D%5Cfrac%7B1%7D%7B2%7D%5Cfrac%7Bd%5BBr_2%5D%7D%7Bdt%7D)
The average rate of consumption of 
![-\frac{d[Br^-]}{dt}=1.76\times 10^{-4} M/s](https://tex.z-dn.net/?f=-%5Cfrac%7Bd%5BBr%5E-%5D%7D%7Bdt%7D%3D1.76%5Ctimes%2010%5E%7B-4%7D%20M%2Fs)
The average rate of formation of ![Br_2=\frac{d[Br_2]}{dt}](https://tex.z-dn.net/?f=Br_2%3D%5Cfrac%7Bd%5BBr_2%5D%7D%7Bdt%7D)
![-\frac{1}{5}\frac{d[Br^-]}{dt}=\frac{1}{2}\frac{d[Br_2]}{dt}](https://tex.z-dn.net/?f=-%5Cfrac%7B1%7D%7B5%7D%5Cfrac%7Bd%5BBr%5E-%5D%7D%7Bdt%7D%3D%5Cfrac%7B1%7D%7B2%7D%5Cfrac%7Bd%5BBr_2%5D%7D%7Bdt%7D)
![\frac{1}{5}\times 1.76\times 10^{-4} M/s=\frac{1}{2}\frac{d[Br_2]}{dt}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B5%7D%5Ctimes%201.76%5Ctimes%2010%5E%7B-4%7D%20M%2Fs%3D%5Cfrac%7B1%7D%7B2%7D%5Cfrac%7Bd%5BBr_2%5D%7D%7Bdt%7D)
![\frac{d[Br_2]}{dt}=7.04\times 10^{-5} M/s](https://tex.z-dn.net/?f=%5Cfrac%7Bd%5BBr_2%5D%7D%7Bdt%7D%3D7.04%5Ctimes%2010%5E%7B-5%7D%20M%2Fs)
is the average rate of formation of bromine gas during the same time interval.
2 ) Rate of the reaction : R
![R=-\frac{1}{6}\frac{d[H^+]}{dt}=\frac{1}{2}\frac{d[Br_2]}{dt}](https://tex.z-dn.net/?f=R%3D-%5Cfrac%7B1%7D%7B6%7D%5Cfrac%7Bd%5BH%5E%2B%5D%7D%7Bdt%7D%3D%5Cfrac%7B1%7D%7B2%7D%5Cfrac%7Bd%5BBr_2%5D%7D%7Bdt%7D)
The average rate of formation of ![Br_2=\frac{d[Br_2]}{dt}=1.14\times 10^{-4} M/s](https://tex.z-dn.net/?f=Br_2%3D%5Cfrac%7Bd%5BBr_2%5D%7D%7Bdt%7D%3D1.14%5Ctimes%2010%5E%7B-4%7D%20M%2Fs)
The average rate of consumption of ![H^+=-\frac{d[H^+]}{dt}](https://tex.z-dn.net/?f=H%5E%2B%3D-%5Cfrac%7Bd%5BH%5E%2B%5D%7D%7Bdt%7D)
![-\frac{1}{6}\frac{d[H^+]}{dt}=\frac{1}{2}\frac{d[Br_2]}{dt}](https://tex.z-dn.net/?f=-%5Cfrac%7B1%7D%7B6%7D%5Cfrac%7Bd%5BH%5E%2B%5D%7D%7Bdt%7D%3D%5Cfrac%7B1%7D%7B2%7D%5Cfrac%7Bd%5BBr_2%5D%7D%7Bdt%7D)
![-\frac{1}{6}\frac{d[H^+]}{dt}=\frac{1}{2}\times 1.14\times 10^{-4} M/s](https://tex.z-dn.net/?f=-%5Cfrac%7B1%7D%7B6%7D%5Cfrac%7Bd%5BH%5E%2B%5D%7D%7Bdt%7D%3D%5Cfrac%7B1%7D%7B2%7D%5Ctimes%201.14%5Ctimes%2010%5E%7B-4%7D%20M%2Fs)
![-\frac{d[H^+]}{dt}=3.42\times 10^{-4} M/s](https://tex.z-dn.net/?f=-%5Cfrac%7Bd%5BH%5E%2B%5D%7D%7Bdt%7D%3D3.42%5Ctimes%2010%5E%7B-4%7D%20M%2Fs)
is the average rate of consumption of
during the same time interval.