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Alborosie
3 years ago
9

Which option describes a similarity and a difference between isotopes of an element?

Chemistry
1 answer:
Brums [2.3K]3 years ago
6 0
Well I do know that they have the same atomic number, but they have a different mass number.

Is that what you were looking for?
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Nuclear fusion, like the example here, produces huge amounts of energy. Consider the statements below. BUT ONE statement provide
vredina [299]

Answer:

Explanation:

Nuclear fusion of a form of nuclear reaction in which two small atomic nuclei combines to form larger ones with the release of a large amount of energy.

For example;

                ²₁H  +  ²₁H   →    ⁴₂He  + Energy

The energy released in a nuclear reaction provides the needed temperature for another set of ²H atoms to fuse. This process in turn yields another ⁴He with the release of a lot of energy. Thus, enormous release of energy accompanies a nuclear reaction.

It is based on this principle that an hydrogen bomb is formed.

5 0
3 years ago
Read 2 more answers
How many moles are there in 36.0g of Beryllium​
Alja [10]

Answer:

4.00 mol

Explanation:

\frac{36.0g Be }{1} *\frac{1 mol}{9.0122 g} = 3.994585118 mol

(If you round Be mass to 9 you get 4 mol)

8 0
3 years ago
A solution is prepared by dissolving 0.5482 grams of iron(III) nitrate in enough water to make 100.0 mL of solution. A 10.00 mL
Kamila [148]

Answer:

C_2=9.066x10^{-4}M

Explanation:

Hello,

In this case, the first step is to compute the molarity of the first solution, for which we consider the molar mass of iron (III) nitrate that is 241.86 g/mol to compute the moles in 100.00 mL (0.1 L) of solution:

M=\frac{0.5482g*\frac{1mol}{241.86 g} }{0.1L}=0.0227 M

Which is actually the concentration of iron (III) ions. Therefore, for 10.00 mL of such solution, the concentration until a dilution to 250.0 mL results being:

C_2=\frac{C_1V_1}{V_2} =\frac{0.0227M*10.00mL}{250.0mL} \\\\C_2=9.066x10^{-4}M

Best regards.

3 0
3 years ago
Consider the reaction 5Br−(aq)+BrO−3(aq)+6H+(aq)→3Br2(aq)+3H2O(l) The average rate of consumption of Br− is 1.76×10−4 M/s over t
trasher [3.6K]

Answer:

1) 7.04\times 10^{-5} M/s is the average rate of formation of bromine gas during the same time interval.

2) 3.42\times 10^{-4} M/s is the average rate of consumption of H^+ during the same time interval.

Explanation:

5Br^-(aq)+BrO_3^{-}(aq)+6H^+(aq)\rightarrow 3Br_2(aq)+3H_2O(l)

1 ) Rate of the reaction : R

R=-\frac{1}{5}\frac{d[Br^-]}{dt}=\frac{1}{2}\frac{d[Br_2]}{dt}

The average rate of consumption of Br^-=1.76\times 10^{-4} M/s

-\frac{d[Br^-]}{dt}=1.76\times 10^{-4} M/s

The average rate of formation of Br_2=\frac{d[Br_2]}{dt}

-\frac{1}{5}\frac{d[Br^-]}{dt}=\frac{1}{2}\frac{d[Br_2]}{dt}

\frac{1}{5}\times 1.76\times 10^{-4} M/s=\frac{1}{2}\frac{d[Br_2]}{dt}

\frac{d[Br_2]}{dt}=7.04\times 10^{-5} M/s

7.04\times 10^{-5} M/s is the average rate of formation of bromine gas during the same time interval.

2 ) Rate of the reaction : R

R=-\frac{1}{6}\frac{d[H^+]}{dt}=\frac{1}{2}\frac{d[Br_2]}{dt}

The average rate of formation of Br_2=\frac{d[Br_2]}{dt}=1.14\times 10^{-4} M/s

The average rate of consumption of H^+=-\frac{d[H^+]}{dt}

-\frac{1}{6}\frac{d[H^+]}{dt}=\frac{1}{2}\frac{d[Br_2]}{dt}

-\frac{1}{6}\frac{d[H^+]}{dt}=\frac{1}{2}\times 1.14\times 10^{-4} M/s

-\frac{d[H^+]}{dt}=3.42\times 10^{-4} M/s

3.42\times 10^{-4} M/s is the average rate of consumption of H^+ during the same time interval.

4 0
4 years ago
Calcium chloride contains only calcium and chloride. what is the formula for this compound? (you will need the periodic table fo
Lady bird [3.3K]
Calcium chloride is CaCl2
4 0
3 years ago
Read 2 more answers
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