The formula for sucrose is C12H22O11 with a molecular mass of approx 342g/mol
% mass of C = 12(12) / 342 × 100% = 42.1%
% mass of H = 22(1) / 342 × 100% = 6.43%
% mass of O = 11(16) / 342 ×100% = 51.5%
I'm fascinated with them myself,lol. Anything dangerous really.
1.They have the power to destroy the world.
2.They can wipe out your enemies.
3.If you are crazy enough to use one of these, your enemies will know not to mess with you
Answer:
the specific heat of the unknown compound is 
Explanation:
Generally the change in temperature of water is evaluated as

Substituting 16.1°C for
and 27.4°C for 


Generally the change in temperature of unknown compound is evaluated as

Substituting 27.4°C for
and 94.3°C for 


Since there is an increase in temperature then heat is gained by water and this can be evaluated as

Substituting 179.1 g for m , 4.18 J/g.C for
(specific heat of water)


Since there is a decrease in temperature then heat is lost by unknown compound and this can be evaluated as

By conservation of energy law
Heat lost = Heat gained
Substituting 306.9 g for
, 8459.6J for

Therefore 

Answer:
- 178 ºC
Explanation:
The ideal gas law states that :
PV = nRT,
where P is the pressure, V is the volume, n is number of moles , R is the gas constant and T is the absolute temperature.
For the initial conditions :
P₁ V₁ = n₁ R T₁ (1)
and for the final conditions:
P₂V₂= n₂ R T₂ where n₂ = n₁/2 then P₂ V₂ = n₁/2 T₂ (2)
Assuming V₂ = V₁ and dividing (2) by Eqn (1) :
P₂ V₂ = n₁/2 R T₂ / ( n₁ R T₁) then P₂ / P₁ = 1/2 T₂ / T₁
4.10 atm / 25.7 atm = 1/2 T₂ / 298 K ⇒ T₂ = 0.16 x 298 x 2 = 95.1 K
T₂ = 95 - 273 = - 178 º C
Answer:
The answer to your question is CuSO₄
Explanation:
To answer your question just remember the following information
- A chemical reaction is divided into sections
reactants and products
reactants on the left side of the reaction
products on the right side of the reaction
- All the symbols have a meaning
(s) means that that compound is in solid phase
(aq) means that that compound is dissolved in solution.
Then, the answer is CuSO₄