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2 years ago

What can be used to determine the relative age of two rocks?

Chemistry

2 answers:

ratelena [41]2 years ago

6 0

B. The presence of unconformities

Alona [7]2 years ago

4 0

The presence of unconformities can be used to determine the relative age of two rocks. Therefore, the correct answer is B

Unconformity refers to a non-depositional surface which separates two strata of different age. Unconformity shows that deposited sedimentary rock was not continuous. Unconformity indicates that the older layer was exposed to erosion before the younger layer.

<h2>Further Explanation</h2>

The upper rocks, that is, the rocks that are higher than the unconformities are younger than those beneath the conformity.

In general, an unconformity indicates the period when no sediments were preserved.

The types of unconformities include

Disconformities: this is a type of unconformity between parallel layers of sedimentary rocks. It represents the time of erosion and they are characterized by some qualities of subarea emotion.
Nonconformity: this is between an ingenious rock and sedimentary rock when the sedimentary rock was placed on eroded igneous rock
Angular unconformity: this is a type of unconformity in which a parallel layer of sedimentary rocks are deposited on eroded layers and generate discordance with the horizontal layers.

Other types of unconformity include:

Paraconformity
Buttress unconformity
Blended unconformity

Therefore, the presence of unconformities can be used to determine the relative age of two rocks.

LEARN MORE:

What can be used to determine the relative age of two rocks? brainly.com/question/2829907
What can be used to determine the relative age of two rocks? brainly.com/question/2825971

KEYWORDS:

unconformities
relative age
rocks
sedimentary rock
rock layers

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Read 2 more answers

179.1 g of water is in a Styrofoam calorimeter of negligible heat capacity. The initial T of the water is 16.1oC. After 306.9 g

taurus [48]

Answer:

the specific heat of the unknown compound is $c_u=0.412J/g \cdot C$

Explanation:

Generally the change in temperature of water is evaluated as

$\Delta T = T_2 -T_1$

Substituting 16.1°C for $T_1$ and 27.4°C for $T_2$

$\Delta T = 27.4 - 16.1$

$=11.3^oC$

Generally the change in temperature of unknown compound is evaluated as

$\Delta T_u = T_3 -T_2$

Substituting 27.4°C for $T_2$ and 94.3°C for $T_3$

$\Delta T = 94.3 - 27.4$

$=66.9^oC$

Since there is an increase in temperature then heat is gained by water and this can be evaluated as

$H_w = mc_w \Delta T$

Substituting 179.1 g for m , 4.18 J/g.C for $c_w$ (specific heat of water)

$H_w = 4.18 * 179.1 * 11.3$

$= 8459.6J$

Since there is a decrease in temperature then heat is lost by unknown compound and this can be evaluated as

$H_u = m_uc_u \Delta T_u$

By conservation of energy law

Heat lost = Heat gained

Substituting 306.9 g for $m_u$ , 8459.6J for $H_u$

$8459.6 = 306.9 * c_u * 66.9$

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3 years ago

In a separate experiment beginning from the same initial conditions, including a temperature Ti of 25.0°C, half the number of mo

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Answer:

- 178 ºC

Explanation:

The ideal gas law states that :

PV = nRT,

where P is the pressure, V is the volume, n is number of moles , R is the gas constant and T is the absolute temperature.

For the initial conditions :

P₁ V₁ = n₁ R T₁ (1)

and for the final conditions:

P₂V₂= n₂ R T₂ where n₂ = n₁/2 then P₂ V₂ = n₁/2 T₂ (2)

Assuming V₂ = V₁ and dividing (2) by Eqn (1) :

P₂ V₂ = n₁/2 R T₂ / ( n₁ R T₁) then P₂ / P₁ = 1/2 T₂ / T₁

4.10 atm / 25.7 atm = 1/2 T₂ / 298 K ⇒ T₂ = 0.16 x 298 x 2 = 95.1 K

T₂ = 95 - 273 = - 178 º C

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3 years ago

Fe(s) + CuSO4(aq) ⇒ Cu(s) + FeSO4(aq)

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Answer:

The answer to your question is CuSO₄

Explanation:

To answer your question just remember the following information

- A chemical reaction is divided into sections

reactants and products

reactants on the left side of the reaction

products on the right side of the reaction

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(aq) means that that compound is dissolved in solution.

Then, the answer is CuSO₄

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