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3 years ago

What can be used to determine the relative age of two rocks?

Chemistry

2 answers:

ratelena [41]3 years ago

6 0

B. The presence of unconformities

Alona [7]3 years ago

4 0

The presence of unconformities can be used to determine the relative age of two rocks. Therefore, the correct answer is B

Unconformity refers to a non-depositional surface which separates two strata of different age. Unconformity shows that deposited sedimentary rock was not continuous. Unconformity indicates that the older layer was exposed to erosion before the younger layer.

<h2>Further Explanation</h2>

The upper rocks, that is, the rocks that are higher than the unconformities are younger than those beneath the conformity.

In general, an unconformity indicates the period when no sediments were preserved.

The types of unconformities include

Disconformities: this is a type of unconformity between parallel layers of sedimentary rocks. It represents the time of erosion and they are characterized by some qualities of subarea emotion.
Nonconformity: this is between an ingenious rock and sedimentary rock when the sedimentary rock was placed on eroded igneous rock
Angular unconformity: this is a type of unconformity in which a parallel layer of sedimentary rocks are deposited on eroded layers and generate discordance with the horizontal layers.

Other types of unconformity include:

Paraconformity
Buttress unconformity
Blended unconformity

Therefore, the presence of unconformities can be used to determine the relative age of two rocks.

LEARN MORE:

What can be used to determine the relative age of two rocks? brainly.com/question/2829907
What can be used to determine the relative age of two rocks? brainly.com/question/2825971

KEYWORDS:

unconformities
relative age
rocks
sedimentary rock
rock layers

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Pure nitrogen (N2) and pure hydrogen (H2) are fed to a mixer. The product stream has 40.0% mole nitrogen and the balance hydroge

LuckyWell [14K]

Explanation:

The given data is as follows.

Mass flow rate of mixture = 1368 kg/hr

$N_{2}$ in feed = 40 mole%

This means that $H_{2}$ in feed = (100 - 40)% = 60%

We assume that there are 100 total moles/hr of gas $(N_{2} + H_{2})$ in feed stream.

Hence, calculate the total mass flow rate as follows.

40 moles/hr of N_{2}/hr (28 g/mol of $N_{2}$ ) + 60 moles/hr of $H_{2}/hr$ (2 g/mol of $H_{2}$ )

$40 \times 28 g/hr + 60 \times 2 g/hr$

= 1120 g/hr + 120 g/hr

= 1240 g/hr

= $\frac{1240}{1000}$ (as 1 kg = 1000 g)

= 1.240 kg/hr

Now, we will calculate mol/hr in the actual feed stream as follows.

$\frac{100 mol/hr}{1.240 kg/hr} \times 1368 kg/hr$

= 110322.58 moles/hr

It is given that amount of nitrogen present in the feed stream is 40%. Hence, calculate the flow of $N_{2}$ into the reactor as follows.

$0.4 \times 110322.58 moles/hr$

= 44129.03 mol/hr

As 1 mole of nitrogen has 28 g/mol of mass or 0.028 kg.

Therefore, calculate the rate flow of $N_{2}$ into the reactor as follows.

$0.028 kg \times 44129.03 mol/hr$

= 1235.612 kg/hr

Thus, we can conclude that the the feed rate of pure nitrogen to the mixer is 1235.612 kg/hr.

3 0

3 years ago

what is the boiling point of the solution resulted from the dissolving of 32.5g of NaCl in 250.0g of water?

suter [353]

Answer:

The boiling point of this solution is 102.28 °C

Explanation:

<u>Step 1:</u> Data given

Mass of Nacl = 32.5 grams

Molar mass of NaCl = 58.45 g/mol

Mass of Water = 250 grams

Boiling point of water = 100°C

<u>Step 2: </u>Calculate number of moles

Number of moles = mass of NaCl / Molar mass of NaCl

Number of moles = 32.5 grams /58.45 g/mol = 0.556 moles

<u>Step 3:</u> Calculate molality

Molality = Number of moles / mass of water

Molality = 0.556 moles / 0.250 kg of water

Molality = 2.224 molal

NaCl releases twice as many moles of ions, the total molality of this solution is also twice: 4.448 molal

Step 4: Calculate boiling point

dT =( 0.512 C / molal)*4.448 molal)

dT = 2.28

The boiling point of this solution is 100 °C + 2.28 °C = 102.28 °C

8 0

3 years ago

Select all that apply. The stability of atomic nuclei is related to the _____. ratio of protons to electrons ratio of neutrons t

Marat540 [252]

The stability of atomic nuclei relies on the forces within the atom that balance out the charge. The electrons have the power to make an atom negatively or positively charged, but neutrons allow the atom to be electrically neutral regardless. The gravitational pull of protons and neutrons in the atomic nuclei keeps the electrons in an orbit, and with less protons than neutrons, electrons will be pulled into the nuclei and make the atom unstable; with less neutrons than protons, the electrons will be repelled and make the atom unstable. Therefore, the number and ratio of protons to neutrons are the factors that make an atom stable.

Answer: ratio of neutrons to protons and number of protons and neutrons

Hope this helps!

6 0

4 years ago

Read 2 more answers

A student thermally decomposed a 0.150 gram sample of impure potassium chlorate. Manganese dioxide was used as a catalyst in the

harkovskaia [24]

Answer:

1. Vapor pressure of dry oxygen gas = 747.68 torr

2. Volume at STP = 39.97 mL

3. Number of oxygen gas molecules = 1.074 × 10²¹ molecules

4. Percent purity of KClO3 = 97.3 %

Explanation:

The balanced equation for the reaction is given below :

2 KClO3 (s) ------> 2 KCl (s) + 3 O2 (g)

1) Since the water level in the eudiometer was below the outside water level in the beaker,

Vapor pressure of dry oxygen gas = Total pressure + pressure due to difference in water levels - vapor pressure of water

Vapor pressure of water at 20 °C is 17.535 mm (torr).

Pressure due to difference in water level = 4.22 cm × 10mm/cm / 13.534 (13.534 is the density of mercury) = 3.118 mm (torr).

Vapor pressure of dry oxygen gas = 762.10 torr + 3.118 torr - 17.535 torr

Vapor pressure of dry oxygen gas = 747.68 torr

2) P₁ = 747.68 torr; V₁ = 43.60 ml; T1 = 20 °C + 273.15 = 293.15 K

P₂ = 760 torr; T₂ = 273.15 K; V₂ = ?

Using the general gas equation = P₁V₁/T₁ = P₂V₂/T₂

V2₂= P₁V₁T₂ / P₂T₁

V₂ = (747.68 × 43.60 × 273.15 ) / (760 × 293.15)

V₂ = 39.97 ml

Volume of dry oxygen gas at STP = 39.97 mL

3) Volume of oxygen gas at STP 39.97 mL = 0.03997 L

Number of moles of oxygen gas in 0.03997 L = volume of gas at STP /molarvolume at STP

Number of moles of oxygen gas = 0.03997/22.4 L

Number of molecules of oxygen gas = 0.03997/22.4 L × 6.03 × 10²³ molecules

Number of oxygen gas molecules = 1.074 × 10²¹ molecules

e) Number of moles of oxygen gas = 0.03997/22.4 = 0.001784 moles

From the equation, mole ratio of oxygen gas and potassium chlorate is 3 : 2

Moles KClO3 = 2/3 × 0.001784 moles = 0.001189 moles

Molar mass of KClO3 = 39 + 35.5 + 3 × 16 = 122.5 g

Actual mass of KClO3 decomposed = 122.5 grams × 0.001189 mole = 0.146 grams

Percent purity = (actual mass KClO3 decomposed / sample mass of impure KClO3) × 100%

Percent purity = (0.146/0.150) × 100% = 97.3 %

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3 years ago

Who introduces the concept of atomic number?

aleksley [76]

Henry Moseley developed the concept of atomic numbers.

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