Answer:- 12.7%
Solution:- It says, ammonium phosphate is 60.9%. It means if we assume 100 g of the sample then there is 60.9 g ammonium phosphate in it.
Formula of ammonium phosphate is
and it's molecular weight is 149 grams per mol. There is only one P in the formula and so the mass of P in 149 g of ammonium phosphate is 31 g(atomic mass of P).
Now, we could use the proportions to find out the mass percentage of P in the sample.
31 g P is present in 149 g of ammonium phosphate, how many grams of P would be present in 60.9 g of ammonium phosphate. Let's set the proportions as:



This 12.7 g of phosphorous is present in 100 g of the sample means there is 12.7% phosphorous in the sample.
Compound is formed when two or more atomic bond (or atom)
Answer:
Compound A: Propylbenzene
Compound B: Cumene
Explanation:
On this case, we have two clues:
<u>1) The mass spectrometry info</u>
<u>2) The formation of benzoic acid</u>
If we have the formation of benzoic acid with a strong oxidant (
). It means that we have an <u>alky group bonded to benzene</u>. Therefore we have to <u>add three carbons to a benzene</u> ring in order to obtain the mass of the compound (120).
The next question is <u>how these three additional carbons are bonded</u> to the benzene. For this, we have to check the mass info. For compound A we have a <u>fragmentation moeity on 91</u> therefore we have a <u>loss of an ethyl group</u>. Therefore compound A have a <u>linear structure</u> for the aditional three carbons.
For compound B we have a <u>fragmentation moeity on 105</u> this means a loss of 15 units of mass therefore we <u>loss a methyl grou</u>p. This indicates that we have a <u>non linear structure</u> fo the three additional carbons.
See figures 1 and 2.
I hope it helps!
Answer: Silicon dioxide
Explanation:
di is 2 and since oxygen is 2
Yes Animal and plant are cell living