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kykrilka [37]
3 years ago
14

If your mass is 72 kg, your textbook's mass is 3.7 kg, and you and your

Physics
1 answer:
Setler79 [48]3 years ago
6 0

Answer:

The answer is 1.63 x 10 -7 N

Explanation:

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What 3 weather insturements used to measure weather?
JulijaS [17]

Thermometer for measuring air and sea surface temperature

Barometer for measuring atmospheric pressure

Hygrometer for measuring humidity

Anemometer for measuring wind speed

Pyranometer for measuring solar radiation

8 0
2 years ago
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Equation for fluid density
MrMuchimi
<span> (ρ = m / V) hope this helps...:)</span>
7 0
3 years ago
A heat engine extracts 42. 53 kj from the hot reservior and exhausts 17. 69 kj into the cold reservior. what is the work done?
ludmilkaskok [199]

The answer is  24.84kJ.

We apply the expression for the work done by the heat engine is,

W=E_{i n}-E_{o u t}. Putting all given values in the equation we get the final answer.

What is heat engine?

  • A heat engine is a machine that uses heat to generate power. It draws heat from a reservoir, uses that heat to produce work, such as move a piston or lift weights, and then releases that heat energy into the sink.
  • We are given:The heat input is $E_{i n}=42.53 \mathrm{~kJ}$. The heat output is $E_{o u t}=17.69 \mathrm{~kJ}$.
  • The expression for the work done by the heat engine is,W=E_{i n}-E_{o u t}
  • Substituting the given values in the above expression, we will getW =42.53 \mathrm{~kJ}-17.69 \mathrm{~kJ}=24.84kJ.
  • Thus, the work done by the heat engine is 24.84kJ.

To learn more about heat engine visit: brainly.com/question/15735984

#SPJ4

6 0
1 year ago
A machine carries a 100kg cargo to a boat at a rate of 10m/s2. The distance between the ground to the boat is 50ft. If the machi
klasskru [66]

Answer:

50.8 watt

Explanation:

we know that P=W÷t

W=F.S           S-->distance=50 ft= 15.24 m

F=ma

=100×10=1000 N

SO W= 1000×15.24

        =15240 J

NOW

P=W÷t          t=5 mints = 5×60=300 sec

P=15240÷300

P=50.8 watt

8 0
3 years ago
Assume we’re able to travel to your planet and decide to take some fireworks with us to celebrate our journey.
julia-pushkina [17]

Answer:

The horizontal distance covered by the firework will be \frac{1876.8}{g}

Explanation:

Let acceleration due to gravity on the planet be g, initial velocity of the firework be u and angle made with the horizontal be ∅.

writing equation of motion in vertical direction:

v_{y}=u_{y}+(-g) t

u_{y}= u\sin \phi

and v_{y}=0

therefore \frac{u\sin \phi }{g} =t

writing equation of motion in horizontal direction:

s_{x}=u_{x}t

u_{x} = u\cos \phi

therefore the equation becomes s_{x}=\frac{u^{2}   \sin \phi  \cos \phi}{g}

therefore horizontal distance traveled =\frac{u^{2}\sin 2\alpha \phi }{2g}=\frac{1876.8}{g}\frac{m}{s}

5 0
3 years ago
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