Answer:
f = 293.38 Hz
1 st overtone = 586.76 Hz
2 nd overtone = 880.14 Hz
Explanation:
Mass of the string, m =3.4 g = 0.0034 kg
Length of the string, l = 90 cm = 0.90 m
Distance from the bridge, L = 62 cm = 0.62 m
Tension in the string, T = 500 N
Fundamental frequency is given by:
First overtone = 2 × f = 2 × 293.38 =586.76 Hz
Second Overtone = 3×f = 3 × 293.38 = 880.14 Hz