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Sphinxa [80]
3 years ago
5

a rocket initially at rest is fired vertically with an upward acceleration of 10 m/s2. at an altitude of 0.50 km, the engine of

the rocket cuts off (When the engine os off, it accelerates downwards at approximately 10 m/s). What is the maximum altitude it achieves? How long does it take to reach this altitude from launch?
Physics
1 answer:
hichkok12 [17]3 years ago
8 0

Answer:

5x+sin(20)

Explanation:

For seisimic time

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We can salve the problem by using the formula:

F=kx

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From the first situation we can calculate the spring constant, which is given by the ratio between the force applied and the stretching of the spring:

k=\frac{F}{x}=\frac{15 N}{0.075 m}=200 N/m


By using the value of the spring constant we calculated in the first step, we can calculate the new stretching of the spring when a force of 33 N is applied:

x=\frac{F}{k}=\frac{33 N}{200 N/m}=0.165 m

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