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kupik [55]
3 years ago
15

Which statement about Delta.Hf is true?

Chemistry
2 answers:
Novay_Z [31]3 years ago
3 0

Answer:

  • <u><em>It is positive when the bonds of the product store more energy than those of the reactants.</em></u> (the second statement)

Explanation:

ΔHf is the change of enthalpy during the reaction, which is equal to the sum of enthaply  changes of the products less the sum of the enthalpy changes of the reactants.

  • ΔHf = ∑ (ΔH products)  - ∑ (ΔH reactants)

  • ΔHf = ΔH rxn

Also, ΔHrxn, per definition, is the potential chemical energy stored in the bonds of the products less the chemical potential energy stored in the bonds of the reactants.

Then, when the potential chemical energy stored in the bonds of the products is greater than the chemical potential energy stored in the bonds of the reactants ΔHrxn is positive.

Hence, you conclude that ΔHf is positive when the bonds of the product store more energy than those of the reactants (second statement from the choices).

Some brief comments about the other statements:

  • The standard enthalpy of formation, ΔHf, is zero for an element in its standard state, not for a compound.

  • For a compound the enthalpy of formation at 25ºC and 1 atm (the standard state) may be positive or negative.

  • Also, note that the standard state for any element is not liquid: some are solids, some are gases, and some are liquids at 25ºC and 1 atm.

mote1985 [20]3 years ago
3 0

Answer:

B

Explanation:

answer on edg :)

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Answer
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Explanation
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Which is the limiting reagent in the following reaction given that you start with 15.5 g of Na2S and 12.1 g CuSO4? Reaction: Na2
NemiM [27]

Answer:

CuSO4

Explanation:

Na2S + CuSO4 → Na2SO4 + CuS

The reaction is balanced (same number of elements in each side)

To determine limiting reagent you need to know the moles you have of each.

Molar mass Na2S = 23 * 2 + 32 = 78

Molar mass CuSO4 = 63.5 + 32 + 16 * 4 = 159.5

Na2S mole = 15.5 / 78 = 0.2

CuSO4 mole = 12.1/159.5 = 0.076

*Remember mole = mass / MM

With that information now you have to divide each moles by its respective stoichiometric coefficient

Na2S stoichiometric coefficient : 1

Na2S : 0.2 / 1 = 0.2

CuSO4 stoichiometric coefficient: 1

CuSO4: 0.076 / 1 = 0.076

The smaller number between them its the limiting reagent, CuSO4

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