13.45 At the bottom of a large vacuum chamber whose walls are at 300 K, a black panel 0.1 m in diameter is maintained at 77 K. T
o reduce the heat gain to this panel, a radiation shield of the same diameter D and an emissivity of 0.05 is placed close to the panel. Calculate the net rate of heat gain to the panel. The illustration is of the bottom of a large vacuum chamber is of square shape whose walls are at 300 K, a black panel is maintained at 77 K. A radiation shield of the same diameter D is placed close to the panel.
1 answer:
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Solution :
Let kg
m/s
Let and
are the speeds of the disk
and
after the collision.
So applying conservation of momentum in the y-direction,
Therefore, the disk 2 have greater velocity and hence more kinetic energy after the collision.
Now applying conservation of momentum in the x-direction,
m/s
So,
= 4.33 m/s
Therefore, speed of the disk 2 after collision is 4.33 m/s