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Tcecarenko [31]
3 years ago
10

Please, Please Help!!!!!! The activated complex is located at point: -B -C

Chemistry
2 answers:
Lena [83]3 years ago
7 0

The activated complex is located at point \boxed{\text{B}}.

Further Explanation:

The chemical substances that were initially present at the start of a chemical reaction are called reactants whereas the ones produced after the completion of a reaction are known as products.

During the occurrence of a chemical reaction, the bonds between the reactant molecules are broken and some new bonds are formed, resulting in the formation of products. But reactants are not readily converted into products. Between these two substances, there is also a formation of a highly energetic intermediate, known as activated complex. Due to its high energy, it is very unstable and dissociates to form products. In the reaction profile diagram, it is present at the point of highest energy. So it has energy greater than both the reactants as well as products.

In the given diagram, B represents the point of highest energy so the activated complex is located at this point. Here, A represents the energy of reactant molecules, C represents the products that have energy lower than both the reactants and the activated complex and therefore its formation is possible due to lower energy and higher stability.

Learn More:

  1. What is the half-life of the reaction? brainly.com/question/8907464
  2. Rate of chemical reaction: brainly.com/question/1569924

Answer Details:

Grade: Senior School

Chapter: Chemical Kinetics

Subject: Chemistry

Keywords: reactants, products, intermediate, activated complex, B, C, energy, lower energy, higher stability, A, B, C, unstable.

TiliK225 [7]3 years ago
5 0

Answer : The activated complex is located at point B.

Explanation :

Activated complex : When the reactant molecules absorb energy, their bonds are loosened and new loose bonds are formed between them.

The intermediate thus formed is known as an activated complex or it is also known as transition state complex.

It is unstable and immediately dissociates to form the stable products. In the graph, it is present at the higher point.

In the given graph, A represent the reactant energy, B represent the activated complex, C represent the product, Y represent the reactant, X energy of the reaction and Z activation energy.

Hence, The activated complex is located at point B.

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adoni [48]

Answer: assume pathogens are present and treat the samples accordingly

Explanation:

When investigators are unable to conclusively ascertain the source of a biological sample found at a crime scene, the correct thing to do is to treat it as if pathogens are present in it and handle it according to set rules on how to handle pathogens.

This is done to ensure that if a pathogen is indeed present, it would not cause a health emergency by infecting those who come in contact with the samples at the scene.

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3 years ago
_______ is the amount of heat necessary to raise the temperature of 1 gram of a substance by 1 degree Kelvin. A. A calorie B. En
Maksim231197 [3]
<h2>The required option d) "specific heat" is correct.</h2>

Explanation:

  • To raise the temperature of any substance or material of certain mass to respective temperature it requires some amount of heat.
  • Specific heat is the amount of heat necessary to raise the temperature of the substance of 1 gram to 1 Kelvin.
  • It is the amount of heat which is required to raise the temperature per unit mass to per unit temperature.
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3 years ago
A liquid has an empirical formula CCl2, and a boiling point of 1 21 oC. When vapourised, the gaseous compound has a density of 4
Darya [45]

Based on the data given, the molar mass of the gas is 165.5 g/mol while the molecular weight of the gas is 165.5 amu

<h3>How can molar mass of a gas be obtained from density, temperature and pressure?</h3>

The molar mass of a gas can be obtained from density, temperature and pressure using the formula below:

  • molar mass = density × molar gas constant × temperature/pressure

Molar gas constant, R = R = 0.082 L.atm/mol/K.

Temperature = 150 °C = 423 K

Pressure = 785 torr = 1.033 atm

density = 4.93 g/L

molar mass of gas = 4.93 × 0.082 × 423/1.033

molar mass of gas = 165.5 g/mol

Then, molecular weight of the gas = 165.5 amu

Therefore, the molar mass of the gas is 165.5 g/mol while the molecular weight of the gas is 165.5 amu

Learn more about molar mass of a gas at: brainly.com/question/26215522

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2 years ago
How many liters of hydrogen gas will be produced at STP from the reaction of 7.179×10^23 atoms of magnesium with 54.219g of phos
Alexeev081 [22]

Answer: The volume of hydrogen gas produced will be, 12.4 L

Explanation : Given,

Mass of H_3PO_4 = 54.219 g

Number of atoms of Mg = 7.179\times 10^{23}

Molar mass of H_3PO_4 = 98 g/mol

First we have to calculate the moles of H_3PO_4 and Mg.

\text{Moles of }H_3PO_4=\frac{\text{Given mass }H_3PO_4}{\text{Molar mass }H_3PO_4}

\text{Moles of }H_3PO_4=\frac{54.219g}{98g/mol}=0.553mol

and,

\text{Moles of }Mg=\frac{7.179\times 10^{23}}{6.022\times 10^{23}}=1.19mol

Now we have to calculate the limiting and excess reagent.

The balanced chemical equation is:

3Mg+2H_3PO_4\rightarrow Mg(PO_4)_2+3H_2

From the balanced reaction we conclude that

As, 3 mole of Mg react with 2 mole of H_3PO_4

So, 0.553 moles of Mg react with \frac{2}{3}\times 0.553=0.369 moles of H_3PO_4

From this we conclude that, H_3PO_4 is an excess reagent because the given moles are greater than the required moles and Mg is a limiting reagent and it limits the formation of product.

Now we have to calculate the moles of H_2

From the reaction, we conclude that

As, 3 mole of Mg react to give 3 mole of H_2

So, 0.553 mole of Mg react to give 0.553 mole of H_2

Now we have to calculate the volume of H_2  gas at STP.

As we know that, 1 mole of substance occupies 22.4 L volume of gas.

As, 1 mole of hydrogen gas occupies 22.4 L volume of hydrogen gas

So, 0.553 mole of hydrogen gas occupies 0.553\times 22.4=12.4L volume of hydrogen gas

Therefore, the volume of hydrogen gas produced will be, 12.4 L

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M=7M(H₂O)

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