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3 years ago

What’s 2.3 miles into kilometers

Physics

1 answer:

True [87]3 years ago

8 0

3.701 kilometers hope that helps

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The MAC is 58 inches, The CG limits are from 26% to 43% MAC. If the CG is found to be

eimsori [14]

By working with percentages, we want to see how many inches is the center of gravity out of the limits. We will find that the CG is 1.45 inches out of limits.

<h3>What are the limits?</h3>

First, we need to find the limits.

We know that the MAC is 58 inches, and the limits are from 26% to 43% MAC.

So if 58 in is the 100%, the 26% and 43% of that are:

26% → (26%/100%)*58in = 0.26*58 in = 15.08 in
43% → (43%/100%)*58in = 0.43*58 in = 24.94 in.

But we know that the CG is found to be 45.5% MAC, then it measures:

(45.5%/100%)*58in = 0.455*58in = 26.39 in

We need to compare it with the largest limit, so we get:

26.39 in - 24.94 in = 1.45 in

This means that the CG is 1.45 inches out of limits.

If you want to learn more about percentages, you can read:

brainly.com/question/14345924

6 0

2 years ago

A grandfather clock has a pendulum that consists of a thin brass disk of radius r = 13.62 cm and mass 1.199 kg that is attached

Feliz [49]

Answer:

Explanation:

Expression for time period of a pendulum is as follows

T = $2\pi\sqrt{\frac{l}{g} }$

l is length of pendulum from centre of bob and g is acceleration due to gravity

Given

Time period T = 1.583

g = 9.846

Substituting the values

1.583 = $2\pi\sqrt{\frac{l}{9.846} }$

l = $\frac{(1.583)^2\times9.846}{4\times(\frac{22}{7})^2 }$

l = .6244 m

= 62.44 cm

Length of rod = length of pendulum - radius of bob

= 62.44 - 13.62

= 48.82 cm

= .488 m

8 0

3 years ago

A block with a mass M = 4.85 kg is resting on a slide that has a curved surface. There is no friction. The speed of the block af

natali 33 [55]

Answer:

The correct option is a

Explanation:

From the question we are told that

The mass of the block is $m = 4.84 \ kg$

The height of the vertical drop is $h = 19.6 \ m$

Generally from the law of energy conservation , the potential energy at the top of the slide is equal to the kinetic energy at the point after sliding this can be mathematically represented as

$PE = KE$