Question

As an electron moves through a region of space, its speed decreases from 6.03 × 106 m/s to 2.45 × 106 m/s. the electric force is the only force acting on the electron. (a) did the electron move to a higher potential or a lower potential? (b) across what potential difference did the electron travel?

Answer 1

Answer:

a) It moved to a lower potential

b) ΔФ = - 86.28 Volt

Explanation:

The energy of an charged particle and the electric potential are related by the potential al kinetic energies:

$\frac{\text{mv}^2}{2} = e\phi$

If we consider an electron:

m = 9.10938*10^-31 Kilogram

e = 1.60218*10^-19 Coulomb

And the potential diference may be calculed by:

$\Delta \phi =\frac{m \left(v_f^2-v_i^2\right)}{2 e}$

Replacing all the values we get:

ΔФ = - 86.28 (Kilogram Meter^2)/(Coulomb Second^2) = -86.28 Volts