1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Tanya [424]
2 years ago
7

A revolving searchlight on an island 6 miles from shore turns at the rate of 2 revolutions per minute in the clockwise direction

. At what speed is the light beam travelling along the straight shoreline the instant it makes an angle of 45◦ with the shoreline? (recall: one revolution = 2π radians.)
Physics
1 answer:
Molodets [167]2 years ago
8 0

Answer:

 Revolving velocity = 2 km/s

Explanation:

Velocity of circular motion = Radius x Angular velocity.

Angular velocity, ω = 2πf, where f is the frequency of circular motion.

Here frequency, f = 2 revolutions per minute

                     f = \frac{2}{60} =0.033revolutions per second.  

Angular velocity, ω = 2πf = 0.209 radians/second.

Radius = 6 miles = 6 x 1.6 x 10³ = 9.6 x 10³ m.

Linear velocity =  9.6 x 10³ x 0.209 = 2006.4 m/s= 2 km/s

Revolving velocity = 2 km/s

You might be interested in
Can a goalkeeper at his goal kick a soccer ball into the opponent’s goal without the ball touching the ground? The distance will
zmey [24]

The goalkeeper at his goal cannot kick a soccer ball into the opponent’s goal without the ball touching the ground

Explanation:

Consider the vertical motion of ball,

We have equation of motion v = u + at

     Initial velocity, u  = u sin θ

     Final velocity, v =  0 m/s    

     Acceleration = -g

     Substituting

                      v = u + at  

                      0 = u sin θ - g t

                      t=\frac{usin\theta }{g}

This is the time of flight.

Consider the horizontal motion of ball,

        Initial velocity, u =  u cos θ

        Acceleration, a =0 m/s²  

        Time, t=\frac{usin\theta }{g}  

     Substituting

                      s = ut + 0.5 at²

                      s=ucos\theta \times \frac{usin\theta }{g}+0.5\times 0\times (\frac{usin\theta }{g})^2\\\\s=\frac{u^2sin\theta cos\theta}{g}\\\\s=\frac{u^2sin2\theta}{2g}

This is the range.

In this problem

              u = 30 m/s

              g = 9.81 m/s²

              θ = 45° - For maximum range

Substituting

               s=\frac{30^2\times sin(2\times 45)}{2\times 9.81}=45.87m

Maximum horizontal distance traveled by ball without touching ground is 45.87 m, which is less than 95 m.

So the goalkeeper at his goal cannot kick a soccer ball into the opponent’s goal without the ball touching the ground

6 0
3 years ago
To practice Tactics Box 9.1 Calculating the Work Done by a Constant Force. Recall that the work W done by a constant force F⃗ at
insens350 [35]

Answer:

The vector magnitudes F and r are always postive, so the sign o W is determined entirely by the angle e between the force and the displacement.Submit Figure 1 off 1 part C

3 0
2 years ago
Read 2 more answers
How come walking converts chemical energy into mechanical energy
tekilochka [14]
Chemical energy (calories) is converted by your body walking on the surface into mechanical/kinetic energy
3 0
2 years ago
Read 2 more answers
Your brother is insisting that you’ll never hear a sound produced behind a barrier wall at the end of your yard you notice that
Tresset [83]

Answer

D.Diffraction

Explanation

Diffraction is a property that is experienced by waves when they come across a barrier when they are in motion.

The ways tends to curve behind the barrier. This is called diffraction of waves.

Now, sound is a wave and it also experience diffraction. . So the brother will be able to hear the sound due to diffraction

8 0
3 years ago
Read 2 more answers
Why to astronauts appear weightless while they are filmed performing activities inside the orbiting space shuttle?
vagabundo [1.1K]
<h2>Answer: The astronauts are falling at the same rate as the space shuttle as it orbits around earth</h2>

The astronauts seem to float because they are in free fall just like the spacecraft.

However, although they are constantly falling on the Earth, they do not fall because the ship orbits at a sufficient speed (in the same direction of rotation of the Earth) so that the centrifugal force is balanced with the Earth's gravitational pull.

In other words:

The spaccraft and the astronauts are in free fall but the Earth's surface will never be reached as long as they does not decrease the speed.

Then, as they accelerate toward Earth (regardless of their mass), it curves beneath them and never comes close.

That's why astronauts, having the same acceleration as the spacecraft, feel weightless and see themselves floating.

8 0
2 years ago
Read 2 more answers
Other questions:
  • Coulomb is a very large unit for practical use. Justify your answer if 10^10 electrons are transferred from a body/second
    10·1 answer
  • Coulomb's law is expressed mathematically as
    10·1 answer
  • Zero gauge wire has a diameter of 0.32in and can carry a sustained current of 150A safely. What is the magnetic field a distance
    13·1 answer
  • A thin rod (length = 2.97 m) is oriented vertically, with its bottom end attached to the floor by means of a frictionless hinge.
    10·1 answer
  • A researcher measures the thickness of a layer of benzene (n = 1.50) floating on water by shining monochromatic light onto the f
    8·1 answer
  • A 49.6-kg crate rests on a level floor at a shipping dock. The coefficients of static and kinetic friction are 0.584 and 0.399,
    11·1 answer
  • ! ' 30 !! !
    12·1 answer
  • A 12.0 kg object is stationary on a surface that is inclined 30.0° relative to the horizontal. The coefficient of friction is 0.
    12·1 answer
  • A car starts at point A from rest. It returns to point A in 30 seconds. The race from start to finish is 1 mile.
    15·1 answer
  • Objects 1 and 2 attract each other with a gravitational force
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!