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Troyanec [42]
4 years ago
7

Why a soccer ball that is quickly rolling across a grass field slows and finally stops rolling

Physics
2 answers:
Arturiano [62]4 years ago
5 0
Friction accord while the ball was rolling in the grass and slowed it down until it finally came to a stop
jenyasd209 [6]4 years ago
4 0
This is because of friction. If you want to add extra detail you can say that this ties in with Newton's First Law of Motion, which states that an object moving at a constant speed will stay moving at a constant speed unless there is an opposite force, and in this case, the opposite force against the ball is friction.
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Explanation:

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Read 2 more answers
A polar bear runs at a speed of 11 m/s and has a mass of 380.2 kg. How much Kinetic energy does the bear have?
Yanka [14]

Answer:

\boxed{\sf Kinetic \ energy \ of \ the \ bear (KE) = 23002.1 \ J}

Given:

Mass of the polar bear (m) = 6.8 kg

Speed of the polar bear (v) = 5.0 m/s

To Find:

Kinetic energy of the polar bear (KE)

Explanation:

Formula:

\boxed{ \bold{\sf KE =  \frac{1}{2} m {v}^{2} }}

Substituting values of m & v in the equation:

\sf \implies KE =  \frac{1}{2}  \times 380.2 \times  {11}^{2}

\sf \implies KE = \frac{1}{ \cancel{2}}  \times  \cancel{2} \times 190.1 \times 121

\sf \implies KE = 190.1 \times 121

\sf \implies KE = 23002.1 \: J

\therefore

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5 0
3 years ago
Consider the equation . The dimensions of the variables v, x, and t are , , and , respectively. The numerical factor 3 is dimens
Vinvika [58]

Answer:

Part of the question is missing but here is the equation for the function;

Consider the equation v = (1/3)zxt2. The dimensions of the variables v, x, and t are [L/T], [L], and [T] respectively.

Answer = The dimension for z = 1/T3 i.e 1/ T - raised to power 3

Explanation:

What is applied is the principle of dimensional homogenuity

From the equation V = (1/3)zxt2.

  • V has  a dimension of [L/T]
  • x has a dimension of [L]
  • t has a dimension of [T]
  • from the equation, make z the subject of the relation
  • z = v/xt2 where 1/3 is treated as a constant
  • Substituting into the equation for z
  • z = L/T / L x T2
  • the dimension for z = 1/T3 i.e 1/ T - raised to power 3
5 0
3 years ago
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