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Troyanec [42]
3 years ago
7

Why a soccer ball that is quickly rolling across a grass field slows and finally stops rolling

Physics
2 answers:
Arturiano [62]3 years ago
5 0
Friction accord while the ball was rolling in the grass and slowed it down until it finally came to a stop
jenyasd209 [6]3 years ago
4 0
This is because of friction. If you want to add extra detail you can say that this ties in with Newton's First Law of Motion, which states that an object moving at a constant speed will stay moving at a constant speed unless there is an opposite force, and in this case, the opposite force against the ball is friction.
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Cuales son los fallos en la teoría del big bang clasico?
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8 0
3 years ago
I NEED HELP SOLVING THIS!!!!!!!!!!!!
Neko [114]

Answer:

Yes

Explanation:

The given parameters are;

The speed with which the fastball is hit, u = 49.1 m/s (109.9 mph)

The angle in which the fastball is hit, θ = 22°

The distance of the field = 96 m (315 ft)

The range of the projectile motion of the fastball is given by the following formula

Range = \dfrac{u^2 \times sin(2\cdot \theta)}{g}

Where;

g = The acceleration due to gravity = 9.81 m/s², we have;

Range = \dfrac{49.1^2 \times sin(2\times22^{\circ})}{9.81} \approx 170.71 \ m

Yes, given that the ball's range is larger than the extent of the field, the batter is able to safely reach home.

7 0
3 years ago
A 0.50-kg croquet ball is initially at rest on the grass. When the ball is struck by a mallet, the average force exerted on it i
NeTakaya

The impulse given to the ball is equal to the change in its momentum:

J = ∆p = (0.50 kg) (5.6 m/s - 0) = 2.8 kg•m/s

This is also equal to the product of the average force and the time interval ∆t :

J = F(ave) ∆t

so that if F(ave) = 200 N, then

∆t = J / F(ave) = (2.8 kg•m/s) / (200 N) = 0.014 s

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1 year ago
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