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nikklg [1K]
3 years ago
8

The absorbance of a crystal violet solution in water (density is 1.00 g/mL) is measured in a 1.0 cm cuvette. The absorbance is 0

.614 and the molar absorptivity coefficient is The molecular weight of crystal violet is 407.98 g/mol. What is the molar concentration of the solution?
Chemistry
1 answer:
spin [16.1K]3 years ago
4 0

Answer : The molar concentration of solution is 7.06\times 10^{-6}mol/L

Explanation :

Using Beer-Lambert's law :

A=\epsilon \times C\times l

where,

A = absorbance of solution  = 0.614

C = molar concentration of solution = ?

l = path length = 1.0 cm

\epsilon = molar absorptivity coefficient = 87000M^{-1}cm^{-1}   (assume)

Now put all the given values in the above formula, we get:

0.614=(87000M^{-1}cm^{-1})\times C\times (1.0cm)

C=0.00000705747mol/L=7.06\times 10^{-6}mol/L

Therefore, the molar concentration of solution is 7.06\times 10^{-6}mol/L

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For the following balanced equation: 3 Cu(s) + 8 HNO3(aq) → 3 Cu(NO3)2(aq) + 2 NO(g) + 4 H2O(l) a) How many moles of HNO3 will r
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a) How many moles of HNO3 will react with 10 moles of Cu?

For 3 moles Cu we need 8 moles HNO3 to produce 3 moles Cu(NO3)2, 2 moles NO and 4 moles H2O

For 10 moles Cu we need 8/3 *10 = <u>26.67 moles HNO3 </u>

b) How many moles of NO will form if 0.50 moles of Cu reacts?

For 3 moles Cu we need 8 moles HNO3 to produce 3 moles Cu(NO3)2, 2 moles NO and 4 moles H2O

For 0.50 moles Cu we'll have 2/3 *0.50 = <u>0.33 moles NO</u>

c) If 0.80 moles of H2O forms, how much NO must also form?

For 3 moles Cu we need 8 moles HNO3 to produce 3 moles Cu(NO3)2, 2 moles NO and 4 moles H2O

If 0.80 moles H2O is produced, 0.80/2 = <u>0.40 moles NO is produced</u>

d) How many moles of Cu are in 10.0 grams of Cu?

Moles Cu = 10.0 grams / 63.55 g/mol = 0.157 moles

In 10.0 grams Cu we have <u>0.157 moles Cu</u>

e) If 10.0 g of Cu reacts, how many moles of NO will form?

10.0 grams Cu = 0.157 moles

For 3 moles Cu we need 8 moles HNO3 to produce 3 moles Cu(NO3)2, 2 moles NO and 4 moles H2O

For 0.157 moles Cu we'll have 2/3 * 0.157 = <u>0.105 moles NO</u>

f) If 10.0 g of Cu reacts, how many grams of HNO3 are required?

10.0 grams Cu = 0.157 moles

For 3 moles Cu we need 8 moles HNO3 to produce 3 moles Cu(NO3)2, 2 moles NO and 4 moles H2O

For 0.157 moles Cu we'll need 0.419 moles HNO3

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For 0.317 moles HNO3 we'll have 0.317/4 = 0.0793 moles NO

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