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3 years ago

At 25 °C and 795 Torr, carbon dioxide has a solubility of 0.0356 in water. What is its solubility at 25 °C and 1590 Torr

Chemistry

1 answer:

bulgar [2K]3 years ago

7 0

Answer:

C₂ = 0.0712

Explanation:

Given data:

Pressure 1 = 795 torr

Solubility = 0.0356

Pressure 2 = 1590 torr

Solubility = ?

Solution;

Pressure and solubility are both directly proportional to each other.

P₁/C₁ = P₂/C₂

795 /0.0356 = 1590 / C₂

C₂ = 1590 × 0.0356 / 795

C₂ = 56.604 /795

C₂ = 0.0712

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The empirical formula of a gaseous fluorocarbon is CF2. At a certain temperature and pressure, a 1-L volume holds 8.93 g of this

dimaraw [331]

Answer:

C₄F₈

Explanation:

Using their mole ratio to compute their mass

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x / 12.01067 = 1.70 / 37.99687

cross multiply

x = ( 1.70 × 12) / 37.99687 = 20.4 / 37.99687 = 0.53688 g

mass of one mole of CF₂ = 0.53688 + 1.70 = 2.23688 g

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3 years ago

Determine the molecular formula for the compound with a molar mass of 46.08 g/mol and the following percent compostion:

kramer

Answer:

$\large\boxed{\large\boxed{CH_6N_2}}$

Explanation:

1. First determine the empirical formula.

a) Base: 100 g of compound

mass atomic mass number of moles

g g/mol mol

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H 13.13 1.008 13.13/1.008 = 13.03

N 60.81 14.007 60.81/14.007 = 4.34

b) Divide every number of moles by the smallest number: 2.17

mass number of moles proportion

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H 13.03/2.17 6

N 4.34/2.17 2

c) Empirical formula

$CH_6N_2$

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2. Molecular formula

Since the mass of one unit of the empirical formula is equal to the molar mass of the compound, the molecular formula is the same as the empirical formula:

$CH_6N_2$

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Answer:

Explanation:

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Answer:

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