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Tasya [4]
3 years ago
9

Cuantos gramos de sulfato de plomo (II) se requieren para preparar 200mL una solución de esta sal a una concentración de 100 ppm

. Si se toma una muestra de 30 mL de la disolución anterior y se diluye en 1000 mL de agua, ¿cuál es la concentración de la disolución?
Chemistry
1 answer:
DiKsa [7]3 years ago
6 0

Answer:

0.020g de sulfato de plomo se requieren

La concentración de la solución diluida es de 3ppm

Explanation:

Las partes por millón (ppm) son definidas como:

miligramos soluto / 1L solución.

Si deseas preparar una solución a 100ppm de sulfato de plomo (II) necesitas 100mg de este sulfato en 1L. En 200mL = 0.200L vas a necesitar:

0.200L × (100mg / 1L) = 20mg de sulfato de plomo (II).

Como 1000mg = 1g,

20mg × (1g / 1000mg) = 0.020g de sulfato de plomo se requieren.

Ahora, se van a tomar 30mL de esta solución y se diluirán a 1000mL. Se diluye la solución:

1000mL / 30mL = 33.33 veces.

Como la solución inicial es de 100ppm, esta dilución genera una solución de concentración:

100ppm / 33.33 = 3ppm

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