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bagirrra123 [75]
3 years ago
8

What is the empirical formula of sulphur dioxide which contains 50% by mass of sulphur​

Chemistry
2 answers:
expeople1 [14]3 years ago
7 0

Answer:

Question what are you doing the same thing you guys have a good time

Explanation:

is this the same question why did they do that and how much they do it

RUDIKE [14]3 years ago
4 0

Answer:

Empirical formula is SO2.

Explanation:

So the fraction of Sulphur is 0.50 and the fraction of  oxygen is 0.50.

Dividing by the atomic masses of sulphur and oxygen:

S = .50 / 32 = 0.015625

O = .50 / 16 = 0.3125

Ratio of S: O =     0.015625/ 0.015625 to 0.3125/ 0.015625    

= 1:2.

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Which statement about the density of warm water is most likely correct?
Damm [24]
Density is a property of a material which describes the mass of a material per unit volume. Density is said to be slightly dependent on temperature. We look at the density of water at different temperatures:
<span>
100 </span>°C: 958.4 kg/m^360 °C: 983.2 kg/m^320 <span>°C</span>: 998.2 kg/m^3

Therefore, warm water has a lower density than water in colder temperature.
3 0
3 years ago
Based on the three formulas shown, use one of them to solve for the purple yellow and red box and explain how you did it.
zysi [14]

P = 11.133 atm (purple)

T = -236.733 °C(yellow)

n = 0.174 mol(red)

<h3>Further explanation  </h3>

Some of the laws regarding gas, can apply to ideal gas (volume expansion does not occur when the gas is heated),:  

  • Boyle's law at constant T, P = 1 / V  
  • Charles's law, at constant P, V = T  
  • Avogadro's law, at constant P and T, V = n  

So that the three laws can be combined into a single gas equation, the ideal gas equation  

In general, the gas equation can be written  

\large {\boxed {\bold {PV = nRT}}}

where  

P = pressure, atm  

V = volume, liter  

n = number of moles  

R = gas constant = 0.08206 L.atm / mol K  

T = temperature, Kelvin  

To choose the formula used, we refer to the data provided

Because the data provided are temperature, pressure, volume and moles, than we use the formula PV = nRT

  • Purple box

T= 10 +273.15 = 373.15 K

V=5.5 L

n=2 mol

\tt P=\dfrac{nRT}{V}\\\\P=\dfrac{2\times 0.08205\times 373.15}{5.5}\\\\P=11.133~atm

  • Yellow box

V=8.3 L

P=1.8 atm

n=5 mol

\tt T=\dfrac{PV}{nR}\\\\T=\dfrac{1.8\times 8.3}{5\times 0.08205}\\\\T=36.42~K=-236.733^oC

  • Red box

T = 12 + 273.15 = 285.15 K

V=3.4 L

P=1.2 atm

\tt n=\dfrac{PV}{RT}\\\\n=\dfrac{1.2\times 3.4}{0.08205\times 285.15}\\\\n=0.174~mol

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